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Mathematics

2 answers:

aalyn [17]3 years ago

7 0

Answer:

w = 59°

Step-by-step explanation:

sides AC and BC are congruent thus Δ ABC is isosceles, then the 2 base angles are congruent, that is

∠ A = ∠ B , so

w = $\frac{180-62}{2}$ = $\frac{118}{2}$ = 59°

Ksju [112]3 years ago

5 0

Answer: 62

Explanation: It's an equilateral triangle

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Write the prime factorization of the number. 18,234

shusha [124]

Answer:

$18234=2\times 3\times 3\times 1013$

Step-by-step explanation:

We are given that a number 18234

We have to find the prime factorization of the number

Prime factorization : The number written is in the product of prime numbers is called prime factorization.

In order to find the prime factorization we will find the factors of given number

$18234=2\times 3\times 3\times 1013$

Hence, the prime factorization of $18234=2\times 3\times 3\times 1013$

3 0

3 years ago

Find the polynomial f(x) of degree 3 with real coefficients that has a y-intercept of 60 and zeros 3 and 1+3i.

Sauron [17]

$\bf \begin{cases} x=3\implies &x-3=0\\ x=1+3i\implies &x-1-3i=0\\ x=1-3i\implies &x-1+3i=0 \end{cases} \\\\[-0.35em] ~\dotfill\\\\ (x-3)(x-1-3i)(x-1+3i)=0 \\\\\\ (x-3)\underset{\textit{difference of squares}}{([x-1]-3i)([x-1]+3i)}=0\implies (x-3)([x-1]^2-[3i]^2)=0 \\\\\\ (x-3)([x^2-2x+1]-[3^2i^2])=0\implies (x-3)([x^2-2x+1]-[9(-1)])=0$

[ correction added, Thanks to @stef68 ]

$\bf (x-3)([x^2-2x+1]+9)=0\implies (x-3)(x^2-2x+10)=0 \\\\\\ x^3-2x^2+10x-3x^2+6x-30=0\implies x^3-5x^2+16x-30=f(x) \\\\\\ \stackrel{\textit{applying a translation with a -2f(x)}}{-2(x^3-5x^2+16x-30)=f(x)}\implies -2x^3+10x^2-32x+60=f(x)$