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Inga [223]
3 years ago
10

What is the correct answer to this equation 2+10×2-5+3=

Mathematics
2 answers:
77julia77 [94]3 years ago
7 0

Answer:

20

Step-by-step explanation:

apply BODMAS

10*2+3+2-5

20

fenix001 [56]3 years ago
3 0
2+20-5+3
22-5+3
17+3
20

The answer is 20
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Find the product mentally. (2j + 7)(2j - 7)
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4j^2 -14j +14j - 49

4j^2 - 49

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Solve the rational equation 8-6/x=5+12/x
Firdavs [7]

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X = 6

Step-by-step explanation:

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Can someone help me with these problems?
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Read 2 more answers
Show that if the vector field F = Pi + Qj + Rk is conservative and P, Q, R have continuous first-order partial derivatives, then
olchik [2.2K]

Answer:

It is proved that \frac{\partial P}{\partial y}=\frac{\partial Q}{\partial x}, \frac{\partial P}{\partial z}=\frac{\partial R}{\partial x}, \frac{\partial Q}{\partial z}=\frac{\partial R}{\partial y}

Step-by-step explanation:

Given vector field,

F=P\uvec{i}+Q\uvec{j}+R\uvec{k}

Where,

P=f_x=\frac{\partial f}{\partial x}, Q=f_y=\frac{\partial f}{\partial y}, R=f_z=\frac{\partial f}{\partial z}

To show,

\frac{\partial P}{\partial y}=\frac{\partial Q}{\partial x}, \frac{\partial P}{\partial z}=\frac{\partial R}{\partial x}, \frac{\partial Q}{\partial z}=\frac{\partial R}{\partial y}

Consider,

\frac{\partial P}{\partial y}=\frac{\partial}{\partial y}(\frac{\partial f}{\partial x})=\frac{\partial^2 f}{\partial y\partial x}=\frac{\partial^2 f}{\partial x\partial y}=\frac{\partial }{\partial x}(\frac{\partial f}{\partial y})=\frac{\partial Q}{\partial x}

\frac{\partial P}{\partial z}=\frac{\partial}{\partial z}(\frac{\partial f}{\partial x})=\frac{\partial^2 f}{\partial z\partial x}=\frac{\partial^2 f}{\partial x\partial z}=\frac{\partial }{\partial x}(\frac{\partial f}{\partial z})=\frac{\partial R}{\partial x}

\frac{\partial Q}{\partial z}=\frac{\partial}{\partial z}(\frac{\partial f}{\partial y})=\frac{\partial^2 f}{\partial z\partial y}=\frac{\partial^2 f}{\partial y\partial z}=\frac{\partial}{\partial y}(\frac{\partial f}{\partial z})=\frac{\partial R}{\partial y}

Hence proved.

4 0
3 years ago
What is (-3)^-9 times (-3)^5
otez555 [7]

Answer:

1/80 or 0.01234568

Step-by-step explanation:

Exponentiation: (-3) ^ (-9) = -5.08052634253E-5 = -1/

19683

Exponentiation: (-3) ^ 5 = -243

= -1/

19683

* (-243) = -1 · (-243)/

19683 · 1

= 243/

19683

= 1 · 243/

81 · 243

= 1/

81

8 0
3 years ago
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