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Dahasolnce [82]
3 years ago
13

Can you please help me. Go to my acc for more help for me :)

Mathematics
2 answers:
Angelina_Jolie [31]3 years ago
8 0
The answer is 164. 5x4=20 and so on
Dmitriy789 [7]3 years ago
8 0

Answer: 107

Step-by-step explanation: Use PEMDAS to solve the equation.

3 + 6 (5 x 4) - 16 (parenthesis)

3 + 6 x 20 - 16 (multiplication)

3 + 120 - 16 (addition)

123 - 16 (subtraction)

107

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Like in money?Is there a specific amount?. or anything more to what I would have?I need more details
4 0
3 years ago
Four points are labeled on the number line.Which point represents the value |-1 1/2|?
alukav5142 [94]

Answer: -1

Step-by-step explanation:

i really don't know but i was taking a test and i guessed it and it was right

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Solve for w:<br> 6w + 7 = 7w + 13
agasfer [191]

Answer:

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3 years ago
The sum of two numbers is 62, and their difference is 8. What are the numbers
Lemur [1.5K]
Sum of two numbers is 62?
Let's call the two numbers a and b

let's find two same numbers that would add up to 62: 31.
31 + 31 = 62

since it said the difference is 8, we have to add 4 to one number and subtract 4 from another.
31 - 4 = 27
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Therefore, the two numbers following the given rules are 27 and 35
7 0
3 years ago
What's the center of a circle whose equation is (x – 14)2 + (y + 21)2 = 64?
kvasek [131]

Answer:

The center of the circle is:

  • \left(a,\:b\right)=\left(14,\:-21\right)

Thus, option (2) is true.

Step-by-step explanation:

The circle equation is given by

\left(x-a\right)^2+\left(y-b\right)^2=r^2

here,

  • r =  raduis
  • center = (a, b)

Given the equation

\left(x-14\right)^2+\left(y+21\right)^2=64

\mathrm{Rewrite}\:\left(x-14\right)^2+\left(y+21\right)^2=64\:\mathrm{in\:the\:form\:of\:the\:standard\:circle\:equation}

\left(x-14\right)^2+\left(y-\left(-21\right)\right)^2=8^2

comparing with the circle equation

\left(x-a\right)^2+\left(y-b\right)^2=r^2

Therefore, the center of the circle is:

  • \left(a,\:b\right)=\left(14,\:-21\right)

Thus, option (2) is true.

7 0
2 years ago
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