Answer:
x value of vertical asymptote and y value of horizontal asymptote
Step-by-step explanation:
The graph of 1/x approaches infinity as x approaches 0 (the vertical asymptote)
As x gets either bigger or smaller, 1/x approaches the x-axis (from above on the positive side, from below on the negative side) (the horizontal asymptote)
Consider 1/(x-5) + 2, at what value of x does the graph 'go nuts' ?
When the bottom of the fraction becomes 0, x - 5 becomes 0 when x = 5, so the vertical asymptote of g(x) is at x=5
What value of y does f(x) approach as x gets more positive or more negative - as x gets bigger (as an example), y approaches 0
What y value does g(x) approach as x gets bigger? Well, as x gets big, 1/(x-5) gets small, approaching 0. The smallest 0 + 2 can get is 2, so y=2 is the horizontal asymptote
Answer:
-8x +6
Step-by-step explanation:
5x−2 from −3x+4 .
This means take the 2nd number and subtract the 1st
-3x +4
-( 5x -2)
----------------
Distribute the negative sign
-3x +4
- 5x +2
----------------
-8x +6
Answer:
$3960
Step-by-step explanation:
12% of $4,500 is 540.
Subtracting the 12% means taking away $540 from $4,500, which gives you $3960
The unit rate for that equation is .33
