Let us make a list of all the details we have
We are given
The cost of each solid chocolate truffle = s
The cost of each cream centre chocolate truffle = c
The cos to each chocolate truffle with nuts = n
The first type of sweet box that contains 5 each of the three types of chocolate truffle costs $41.25
That is 5s+5c+5n = 41.25 (cost of each type of truffle multiplied by their respective costs and all added together)
The second type of sweet box that contains 10 solid chocolate trufles, 5 cream centre truffles and 10 chocolate truffles with nuts cost $68.75
That is 10s+5c+10n = $68.75
The third type of sweet box that contains 24 truffles evenly divided that is 12 each of solid chocolate truffle and chocolate truffle with nuts cost $66.00
That is 12s+12n=$66.00
Hence option C is the right set of equations that will help us solve the values of each chocolate truffle.
bearing in mind that a <u>circle</u> means the round thing, so only the points on the round thing are ON the circle, others like the RC chord or the PQ diameter or the point C are NOT ON the circle.
Answer:
Exact Form:
x= -3/2
Decimal Form:
x= -1.5
Mixed Number Form
x= -1 1/2
Step-by-step explanation:
1 2/3 + 1 5/6
We’ll start by converting the 2/3 to 6ths so we have a common denominator.
Look at the denominator first. 3 x 2 is 6, so we need to multiply the numerator by 2 as well. 2/3 = 4/6.
So we have 1 4/6 + 1 5/6 = 2 9/6
But you know they’ll want you to reduce that so it’s 3 3/6...or 3 1/2.
Let me know where you have questions.
