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Nimfa-mama [501]
2 years ago
8

HELP!!! HELP!!! WILL GIVE BRAINLIEST

Mathematics
2 answers:
vekshin12 years ago
5 0
Sets are greater than 6
Nesterboy [21]2 years ago
3 0

Answer:

(a) Two x plus eight is greater than negative four

(b) x > -6; number line would be an open circle at -6 and the line pointing in the positive direction to be shaded

Step-by-step explanation:

(a)

Note first that the inequality sign ">" means "greater than", so 2x + 8 > -4 in written language is:

<em>Two x plus eight </em><em>is greater than</em><em> negative four</em>

<em />

(b)

We solve this just like how we'd solve it if it were 2x + 8 = -4: isolate the variable first.

Subtract 8 from both sides:

2x + 8 - 8 > -4 - 8

2x > -12

Divide by 2:

x > -12/2

x > -6

So, the solution set is all numbers greater than -6.

Drawn on a number line, we would first place an <em>open circle</em> at -6 (because we are using > rather than ≥, which would include the -6 in the solution set). Then, because our solution set includes all numbers greater than -6, we shade in the part of the line that points in the positive direction, so it should include numbers like -5, -4, -3, -2, -1, 0, 1, 2, ... and so on.

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X^2 - 18x = -80 (add 2x to both sides)
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Find the perimeter of a triangle with points A(1,2), B(1,8), and C(5,5) on a Cartesian coordinate plane.
Assoli18 [71]

Check the picture below.

the distance from 1,2 to 1,8 is simply 6 units, we can read that off the grid.  Now let's see what the other distances are, and add them all up to get the perimeter.

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ A(\stackrel{x_1}{1}~,~\stackrel{y_1}{2})\qquad C(\stackrel{x_2}{5}~,~\stackrel{y_2}{5})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ AC=\sqrt{(5-1)^2+(5-2)^2}\implies AC=\sqrt{4^2+3^2} \\\\\\ AC=\sqrt{25}\implies AC=5 \\\\[-0.35em] ~\dotfill

\bf B(\stackrel{x_1}{1}~,~\stackrel{y_1}{8})\qquad C(\stackrel{x_2}{5}~,~\stackrel{y_2}{5}) \\\\\\ BC=\sqrt{(5-1)^2+(5-8)^2}\implies BC=\sqrt{4^2+3^2} \\\\\\ BC=\sqrt{25}\implies BC=5 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill \stackrel{perimeter}{6+5+5\implies 16}~\hfill

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Answer:

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