I need help with number 9
1 answer:
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PART A
The barn is constructed by the following 2D shapes
Two triangles of height = 4' and base = 20'
Area = 2 × (0.5×4×20) = 80
Two rectangles of length = 20' and width = 15'
Area = 2 × 20 × 15 = 600
Two rectangles of length = 45' and width = 15'
Area = 2 × 45' × 15' = 1350
One base of length = 45' and width = 15'
Area = 45 × 15 = 675
Two rectangles on each on one side of the roof. We have the length = 45' but not the width. We can work out the width by using Pythagoras theorem
w² = 4² + 10²
w² = 16 + 100
w² = 116
w = √116 = 10.77
Area of the two rectangles on the roof part is = 2 ×10.77 × 45 = 969.33
Total area to paint = 969.33+675+1350+600+80 = 3674.33 ≈ 3700 (to the nearest hundreth)
PART B
Numbers of paint cans needed = 3700 ÷ 57 = 64.9 ≈ 65 cans
PART C
Total cost of paint = 65 × 23.50 = $1527.50
PART D
The barn is constructed by a cuboid and a rectangular prism
V of cuboid = length × width × height
V of cuboid = 20 × 45 × 15
V of cuboid = 13500
V of triangular prism = Area of cross section × depth
V = [0.5×4×20] × 45
V = 1800
Total volume = 1800 + 13500 = 15300
The barn is constructed by the following 2D shapes
Two triangles of height = 4' and base = 20'
Area = 2 × (0.5×4×20) = 80
Two rectangles of length = 20' and width = 15'
Area = 2 × 20 × 15 = 600
Two rectangles of length = 45' and width = 15'
Area = 2 × 45' × 15' = 1350
One base of length = 45' and width = 15'
Area = 45 × 15 = 675
Two rectangles on each on one side of the roof. We have the length = 45' but not the width. We can work out the width by using Pythagoras theorem
w² = 4² + 10²
w² = 16 + 100
w² = 116
w = √116 = 10.77
Area of the two rectangles on the roof part is = 2 ×10.77 × 45 = 969.33
Total area to paint = 969.33+675+1350+600+80 = 3674.33 ≈ 3700 (to the nearest hundreth)
PART B
Numbers of paint cans needed = 3700 ÷ 57 = 64.9 ≈ 65 cans
PART C
Total cost of paint = 65 × 23.50 = $1527.50
PART D
The barn is constructed by a cuboid and a rectangular prism
V of cuboid = length × width × height
V of cuboid = 20 × 45 × 15
V of cuboid = 13500
V of triangular prism = Area of cross section × depth
V = [0.5×4×20] × 45
V = 1800
Total volume = 1800 + 13500 = 15300
Answer:
Step-by-step explanation:
Hello!
The variables of interest are:
X₁: Number of cases of polio observed in kids that received the placebo vaccine.
n₁= 201299 total children studied
x₁= 110 cases observed
X₂: Number of cases of polio observed in kids that received the experimental vaccine.
n₂= 200745 total children studied
x₂= 33 cases observed
These two variables have a binomial distribution. The parameters of interest, the ones to compare, are the population proportions: p₁ vs p₂
You have to test if the population proportions of children who contracted polio in both groups are different: p₂ ≠ p₁
a)
H₀: p₂ = p₁
H₁: p₂ ≠ p₁
α: 0.05
Sample proportion placebo p'₁= x₁/n₁= 110/201299= 0.0005
Sample proportion vaccine p'₂= x₂/n₂= 33/200745= 0.0002
Pooled sample proportion p'= (x₁+x₂)/(n₁+n₂)= (110+33)/(201299+200745)= 0.0004
This test is two-tailed, using the critical value approach, you have to determine two critical values:
Then if ≤ -1.96 or if
≥ 1.96, the decision is to reject the null hypothesis.
If -1.96 < < 1.96, the decision is to not reject the null hypothesis.
⇒ = -4.76, the decision is to reject the null hypothesis.
b)
H₀: p₂ = p₁
H₁: p₂ ≠ p₁
α: 0.01
The value of = -4.76 doesn't change, since we are working with the same samples.
The only thing that changes alongside with the level of significance is the rejection region:
Then if ≤ -2.576or if
≥ 2.576, the decision is to reject the null hypothesis.
If -2.576< < 2.576, the decision is to not reject the null hypothesis.
⇒ = -4.76, the decision is to reject the null hypothesis.
c)
Remember the level of significance (probability of committing type I error) is the probability of rejecting a true null hypothesis. This means that the smaller this value is, the fewer chances you have of discarding the true null hypothesis. But as you know, you cannot just reduce this value to zero because, the smaller α is, the bigger β (probability of committing type II error) becomes.
Rejecting the null hypothesis using different values of α means that there is a high chance that you reached a correct decision (rejecting a false null hypothesis)
I hope this helps!