It’s line 4. She subtracted the final from the initial. The distance formula requires you to subtract the initial from the final. That’s the formula for displacement in x and y.
Answer:
The answer is 188
Step-by-step explanation:
because cm is 8 and cm has the exponent of 2 so that will equal 64 and 64 plus the area is 188
9514 1404 393
Answer:
a) w(4w-15)
b) w²
c) w(4w -15) = w²
d) w = 5
e) 5 by 5
Step-by-step explanation:
a) If w is the width, and the length is 15 less than 4 times the width, then the length is 4w-15. The area is the product of length and width.
A = w(4w -15)
__
b) If w is the side length, the area of the square is (also) the product of length and width:
A = w²
__
c) Equating the expressions for area, we have ...
w(4w -15) = w²
__
d) we can subtract the right side to get ...
4w² -15w -w² = 0
3w(w -5) = 0
This has solutions w=0 and w=5. Only the positive solution is sensible in this problem.
The side length of the square is 5 units.
__
e) The rectangle is 5 units wide, and 4(5)-15 = 5 units long.
The rectangle and square have the same width and the same area, so the rectangle must be a square.
The upside down U means the numbers the sets have in common.
Do what is in parenthesis first:
(B ∩ C) = 6 is the only common number in set B and Set C.
A ∩ (B ∩ C) = Would be all the numbers in A plus the number 6 from (B ∩ C).
The answer would be A) {1, 3, 5, 6, 7, 9}
The length of DD' is 5.39 units.
