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Digiron [165]
4 years ago
15

In a sale, normal prices are reduced by 12%

Mathematics
2 answers:
e-lub [12.9K]4 years ago
8 0
12\%-reduce\\
100\%-12\%=88\%-reduced\ price\\
132.88-88\%\\
x\ \ \ \ \ \ \ -100\%\\\\
x=151
gulaghasi [49]4 years ago
3 0
132.88/88=1.51
1.51*100=151
the normal price is £151
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The question is incomplete. The complete question is:

Demi os working on a representation about a famous mathematician for her math class. She decides to make her poster in the shape of a plus sign. What is the total area of Demi's poster? The image and the measurements of the poster are in the attachment.

Answer: Total area = 1360 square inches

Step-by-step explanation: From the attachment, the poster is formed by two rectangles one over the other and a central part, which is a square. So, the total area is the area of the 2 rectangles minus the area of the square

A = Ar - As

As these forms are regular, the area of both is A = width * length

Area of the 2 rectangle:

width = 20 in

length = 12+20+12 = 44 in

There are 2, then:

Ar = 2.20.44

Ar = 1760

Area of the square:

width = length = 20

As = 20²

As = 400

Total Area:

At = Ar - As

At = 1760 - 400

At = 1360

The total area of the poster is <em><u>1360 square inches</u></em>.

4 0
4 years ago
At the beginning of the school year, the 7th grade class at Oak Hill Middle School has 480 students. There are 270 girls and 210
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Answer:

Part 1: 43.75%

Part 2: 44.07%

Step-by-step explanation:

Hello!

(Pt.1) First, set up a ratio 210/480. Next, you use long division I got the percent 43.75. After that, you subtract 6 from the girls group, (because of them moving away and then more coming back.) and 2 from the boys group. Then, you subtract those from the school "population" and you get 472 as the final population. So then you set up another ratio, 208/472. I got a percent of 44.07% from that.

Thanks For Reading!

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2 years ago
Based on probability and if it is appropriate for a decision to be left up to chance, choose every situation that is both statis
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The situations that are both statistically fair and morally fair are Situation 2, Situation 3 and Situation 5

<h3>How to categorize the situations?</h3>

For a situation to be fair, the probability of every outcome must be equal.

We can now analyze each option using the above highlight

<u>Situation 1</u>

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  • Probability of vowel = 5/26
  • Probability of consonant = 21/26

The probabilities of vowels and consonant are not equal.

Hence, this situation is not fair

<u>Situation 2</u>

People = 4

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The probability of each participant is equal in the above scenario i.e. 1/4

Hence, this situation is fair

<u>Situation 3</u>

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The probability of each cousin is equal in the above scenario i.e. 1/5

Hence, this situation is fair

<u></u>

<u>Situation 4</u>

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The probabilities of prime and composite numbers are not equal.

Hence, this situation is not fair

<u>Situation 5</u>

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All probabilities are equal in the above scenario i.e. 1/5

Hence, this situation is fair

Read more about probability at:

brainly.com/question/251701

#SPJ1

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