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spin [16.1K]
3 years ago
7

A rectangle has a perimeter of 84 meters. One dimension is 7 meters. How long is

Mathematics
1 answer:
Lemur [1.5K]3 years ago
6 0

Answer:

The unknown dimension is 35

Step-by-step explanation:

The perimeter of a rectangle is l+l+w+w or 2l+2w (l=length, w=width)

l+l+w+w=84

7+7+w+w=84

14+w+w=84

then we subtract 14 from 84

w+w=70

2w=70

\frac{70}{2}=35

w=35

Let's check our answer

35+35+7+7=84

<u>Hope this helps :-)</u>

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4 + 6d = 34<br> Need help solving
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Answer:

order of operation

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then it is 6d=30

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Step-by-step explanation:

5 0
3 years ago
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PLEASE HELP ASAP THIS IS THE LAST QUESTION AND I AM STUCK!!
Varvara68 [4.7K]
<h3>Answer:  B) 7 units</h3>

===========================================================

Explanation:

The y coordinates of the two points are the same, so we can subtract the x coordinates and apply absolute value

|R - T| = |-6 - 1| = |-7| = 7

Or we can say

|T - R| = |1 - (-6)| = |1 + 6| = |7| = 7

Either way, the two points are 7 units apart.

You could use the distance formula to get the same answer, but that's definitely overkill in my opinion. The trick mentioned above also could work if the x coordinates were the same, but the y coordinates were different. In any other case, you would have to use the distance formula.

5 0
3 years ago
Find the length x to the nearest whole number. A right triangle has a vertical leg of length x units, a base leg with a length o
wel

Complete Question

The diagram for this question is shown on the first uploaded image

Answer:

The value of x is  x = 274 \ unites

Step-by-step explanation:

From the question we are told that

       The length of the vertical length is  x

      The length of the base leg is L = 330 + d units

      The length of the bisecting line segment is h

       The base angle is \theta  = 28^o

       The angle between d and line segment is  \theta_1 =  56^o

For the first angle

         Tan \theta_1 =  \frac{x}{d}

=>     d =  \frac{x}{Tan \theta _1}

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      Tan \theta = \frac{x}{330 + d}

=>     d = \frac{x}{Tan \theta }  -330

So equating the both d

        \frac{x}{Tan \theta _1} =    \frac{x}{Tan \theta }  -330

Substitute values

        \frac{x}{Tan (56)} =    \frac{x}{Tan (28) }  -330

      0.6745 x =    1.880x  -330

       1.20549 x = 330

       x = 274 \ unites

     

   

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