6 pennies, 12 nickels, 8 dimes, 4 quarters = 30 coins
a) add the probability for drawing a dime and drawing a quarter together:
12/30 + 4/30 = 16/30 = 8/15
The probability is 8/15 or 53%
b) multiply the probability for drawing a penny and drawing a nickel:
6/30 x 12/30 = 72/900 = 2/25
The probability is 2/25 or 8%
c) multiply the probability for drawing quarters but take away one of the total coins and the amount of quarters each time:
4/30 x 3/29 x 2/28 = 24/24360 = 1/1015
The probability is 1/1015 or 0.099%
Answer:
It is 5. I got it right on khan academy! Thanks for the answer!
Step-by-step explanation:
Answer:
Read below.
Step-by-step explanation:
If you include going back home, then its
3710 miles × 5 days =
<u>18,550 miles</u>
If you don't include going back home, then it's
3710 miles ÷ 2 × 5 days =
1855 miles × 5 days =
<u>9,275 miles</u>
Given: Yu, Nailah, and Elena each bought between 7 and 9 yards of ribbon Yu bought 3 pieces of ribbon. Nailah bought 5 pieces of ribbon. Elena bought 6 pieces of ribbon.
To find: Who can buy which ribbon
Solution:
Ribbon Sizes
1 2/3 = 5/3 yard
4/5 yard
3 1/2 = 7/2 Yard
Yu, Nailah, and Elena each bought between 7 and 9 yards of ribbon
Yu bought 3 pieces of ribbon
=> 3 * 5/3 = 5
3 * 4/5 = 2.4
3 * 7/2 = 10.5
Nailah bought 5 pieces of ribbon
=> 5 * 5/3 = 8.33
5 * 4/5 = 4
5 * 7 /2 = 17.5
Elena bought 6 pieces of ribbon
=> 6 * 5/3 = 10
6 * 4/5 = 4.8
6 * 7 /2 = 21
Only value between 7 & 9 is 5 * 5/3 = 8.33
hence Nailah only can buy 1 2/3 = 5/3 yard ribbon
or there is some mistake in the data
