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galben [10]
3 years ago
12

Open Picture Need Help With 11 & 12

Mathematics
1 answer:
likoan [24]3 years ago
4 0

Answer:

Step-by-step explanation:

7). (x + 3)(x + 7)

  = x(x + 7) + 3(x + 7)

  = x² + 7x + 3x + 21

  = x² + 10x + 21

8). (4x + 2)(x - 2)

  = 4x(x - 2) + 2(x - 2)

  = 4x² - 8x + 2x - 4

  = 4x² - 6x - 4

9). (3x + 2)(2x + 5)

  = 3x(2x + 5) + 2(2x + 5)

  = 6x² + 15x + 4x + 10

  = 6x² + 19x + 10

10). (x² - 6)(x - 4)

  = x²(x - 4) - 6(x - 4)

  = x³ - 4x² - 6x + 24

11). (x² + 9)(x - 3)

  = x²(x - 3) + 9(x - 3)

  = x³ - 3x² + 9x - 27

12). (4x²- 4)(2x + 1)

  = 4x²(2x + 1) - 4(2x + 1)

  = 8x³ + 4x² - 8x - 4

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What is the vertex of y=-3x^2+6x+15? Help is much appreciated.
DENIUS [597]

Answer:

<u>(1, 18)</u>

Step-by-step explanation:

Rewrite the equation in vertex form by completing the square for -3x^2 + 6x + 15. This = -3(x - 1)^2 + 18.

Set y equal to the new right side.

y = -3(x - 1)

Use the vertex form, y = a(x - h)^2 + k, to determine the values of a, h, and k.

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k = 18

Vertex = (h, k) / (1, 18)

5 0
3 years ago
A rectangular sign has length of 3 and 1/2 ft and a width of 1 and 1/8 ft. Will the area of the sign be greater or less than 3 a
zavuch27 [327]

Answer:

Area = 3\dfrac{15}{16}\ sq\ ft

Area is greater than 3\frac{1}{2} sq ft.

Step-by-step explanation:

Length of rectangular sign board = 3\frac{1}{2} ft

Width of rectangular sign board = 1\frac{1}{8} ft

Area of a rectangle is given by the formula:

A = Length \times Width

To find the area, we are going to multiply 3\frac{1}{2} with 1\frac{1}{8}.

1\frac{1}{8} is greater than 1.

Therefore the multiplication will be greater than 3\frac{1}{2}.

Hence, we can say that area will be greater than 3\frac{1}{2} sq ft.

Area of the sign:

A = 3\dfrac{1}{2}\times 1\dfrac{1}8\\\Rightarrow A = \dfrac{7}{2}\times \frac{9}8\\\Rightarrow A = \dfrac{63}{16}\\\Rightarrow A = 3\dfrac{15}{16}\ sq\ ft

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3 years ago
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