What is the vertex of y=-3x^2+6x+15? Help is much appreciated.

Mathematics

1 answer:

DENIUS [597]2 years ago

5 0

Answer:

(1, 18)

Step-by-step explanation:

Rewrite the equation in vertex form by completing the square for -3x^2 + 6x + 15. This = -3(x - 1)^2 + 18.

Set y equal to the new right side.

y = -3(x - 1)

Use the vertex form, y = a(x - h)^2 + k, to determine the values of a, h, and k.

a = -3

h = 1

k = 18

Vertex = (h, k) / (1, 18)

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Simplify. (-3.9) + (6.01) - (-7.423) -5.513. 2.487. 9.533.

lianna [129]

First, since we must follow PEMDAS, we need to do the operation that is first, which is addition.

-3.9 + 6.01 ← Adding a negative means subtracting, then giving the sign of the bigger number.

So now we solved those and we got this answer: 2.11

Now, we need to subtract and re-write the expression.

2.11 - (-7.423) = 2.11 + 7.423= 9.533

Ok....so now we have our final answer, and we have the choices above.

The only answer that matches ours is the last one.

Final answer: 9.533

Hope I helped ^_^

4 0

3 years ago

Read 2 more answers

Help I do not know how do you do this ?

aliya0001 [1]

$m\angle LKJ=360-m\angle KJM-m\angle JML-m\angle MLK\\
m\angle LKJ=360-132-48-m\angle MLK\\
m\angle LKJ=180-m\angle MLK\\\\
m\angle MLK=180-m\angle KLN\\
m\angle MLK=180-150\\
m\angle MLK=30^{\circ}\\\\
m\angle LKJ=180-30\\
\boxed{m\angle LKJ=150^{\circ}}$