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tatyana61 [14]
3 years ago
5

PLLLLLLSSSSSs helpppppppp

Mathematics
1 answer:
Citrus2011 [14]3 years ago
5 0

Answer:

x = 40

y = 62

Step-by-step explanation:

I figured out the answer by finding the x on the left triangle first by writing an equation:

(3x - 18) + (x + 7) + (x - 9) = 180

once I worked that I plugged in the number which was 40.

Then for the triangle to the right I also plugged in the numbers for x and got 118 degrees I took 180 and subtracted 118 to get my answer of 62 for y.

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What is the solution set to the inequality 5(x - 2)(x + 4) > 0?
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Answer:

You selected the correct answer: {x | x <<em> </em>-4 or x > 2}

Step-by-step explanation:

5(x - 2)(x + 4) > 0

Use FOIL method to expand (x - 2)(x + 4):

5(x^{2} + 2x - 8) > 0

Distribute 5 into (x^{2} + 2x - 8)

5x^{2} + 10x - 40 > 0

Divide all terms by 5 from both sides of the inequality:

\frac{5x^{2}}{5}  + \frac{10x}{5}  - \frac{40}{5} > \frac{0}{5}

x^{2} + 2x - 8 > 0

Factor the trinomial:

(x + 4) ( x - 2)  > 0

x < -4 or x > -2

Therefore, the solution set to the inequality is {x | x < -4 or x > 2}

<em>Interval notation:  </em>(-∞, -4) ∪ (2, ∞)

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3 years ago
Brenda had a balance of -$52 in her account. The bank charged her a fee of $10 for having a negative balance. What is her new ba
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What is the value of AAA when we rewrite \left(\dfrac {6}{17}\right)^{9x}( 17 6 ​ ) 9x (, start fraction, 6, divided by, 17, end
sineoko [7]

We have been given an expression \left(\dfrac {6}{17}\right)^{9x}. We are asked to find the value of A when rewrite our given expression as A^{x}.

To solve our given problem, we will use exponent properties.

Using exponent property a^{mn}=(a^m)^n, we can rewrite our given expression as:

\left(\dfrac {6}{17}\right)^{9x}=\left(\left(\dfrac {6}{17}\right)^9\right)^{x}

Now, we will compare our expression with  A^{x}.

Upon comparing \left(\left(\dfrac {6}{17}\right)^9\right)^{x} with A^{x}, we can see that A=\left(\dfrac {6}{17}\right)^9.

Therefore, the value of A is \left(\dfrac {6}{17}\right)^9.

We can further simplify \left(\dfrac {6}{17}\right)^9 as:

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