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2 years ago

Plz answer my question i will give 100 point and brainliest please

Mathematics

2 answers:

Blababa [14]2 years ago

8 0

Answer:

The missing number is 21

Step-by-step explanation:

21 + 19 = 40

40 ÷ 5 = 8

Aneli [31]2 years ago

3 0

Answer:

Step-by-step explanation:

Let the number is x.

<u>We have equation:</u>

(x + 19)/5 = 8

<u>Solve for x:</u>

x + 19 = 40
x = 40 - 19
x = 21

You might be interested in

Is (-a + b)² = a² - 2ab + b² right or wrong, and why?

antiseptic1488 [7]

Answer:

$\huge\boxed{\sf Right.}$

Step-by-step explanation:

$(-a+b)^2$

Let's apply the formula (x+y)² = x² + 2xy + y²

Here, x = -a and y = b

So,

= (-a)² + 2(-a)(b) + (b)²

= a² - 2ab + b²

Hence, it has been proved that (-a + b)² = a² - 2ab + b².

$\rule[225]{225}{2}$

Hope this helped!

6 0

2 years ago

I need to turn this in by tomorrow!!!!! PLEASE HELP ME.

AlladinOne [14]

Step-by-step explanation:

Alternate interior angles :- 1 , 4

corresponding angles :- 3

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4 0

3 years ago

Please help..................

oksano4ka [1.4K]

Answer:

128.605m^2

Step-by-step explanation:

because the kite has equal sides you can simply just do 8.5m x 10.2m+8.5m x 4.93m :D

8 0

2 years ago

Oil is pumped continuously from a well at a rate proportional to the amount of oil left in the well. Initially there were millio

JulijaS [17]

Answer:

The amount of oil was decreasing at 69300 barrels, yearly

Step-by-step explanation:

Given

$Initial =1\ million$

$6\ years\ later = 500,000$

Required

At what rate did oil decrease when 600000 barrels remain

To do this, we make use of the following notations

t = Time

A = Amount left in the well

So:

$\frac{dA}{dt} = kA$

Where k represents the constant of proportionality

$\frac{dA}{dt} = kA$

Multiply both sides by dt/A

$\frac{dA}{dt} * \frac{dt}{A} = kA * \frac{dt}{A}$

$\frac{dA}{A} = k\ dt$

Integrate both sides

$\int\ {\frac{dA}{A} = \int\ {k\ dt}$

$ln\ A = kt + lnC$

Make A, the subject

$A = Ce^{kt}$

$t = 0\ when\ A =1\ million$ i.e. At initial

So, we have:

$A = Ce^{kt}$

$1000000 = Ce^{k*0}$

$1000000 = Ce^{0}$

$1000000 = C*1$

$1000000 = C$

$C =1000000$

Substitute $C =1000000$ in $A = Ce^{kt}$

$A = 1000000e^{kt}$

To solve for k;

$6\ years\ later = 500,000$

i.e.

$t = 6\ A = 500000$

So:

$500000= 1000000e^{k*6}$

Divide both sides by 1000000

$0.5= e^{k*6}$

Take natural logarithm (ln) of both sides

$ln(0.5) = ln(e^{k*6})$

$ln(0.5) = k*6$

Solve for k

$k = \frac{ln(0.5)}{6}$

$k = \frac{-0.693}{6}$

$k = -0.1155$

Recall that:

$\frac{dA}{dt} = kA$

Where

$\frac{dA}{dt}$ = Rate

So, when

$A = 600000$

The rate is:

$\frac{dA}{dt} = -0.1155 * 600000$

$\frac{dA}{dt} = -69300$

<em>Hence, the amount of oil was decreasing at 69300 barrels, yearly</em>

7 0

2 years ago

What's the slope of 2,3 and 9,4

prohojiy [21]

Slope 1/7 ; easiest way to remember is rise over run

7 0

2 years ago