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2 years ago

Pile of sand has weight of 90kg the sand is put into a small bag, medium bag and a large bag in the ratio 2:3:7

Mathematics

1 answer:

Tju [1.3M]2 years ago

8 0

Answer:

Sand in small bag = 2x = 2(7.5) = 15 kg

Sand in medium bag = 3x = 3(7.5) = 22.5 kg

Sand in a large bag = 7x = 7(7.5) = 52.5 kg

Step-by-step explanation:

Total weight = 90 kg

As 90 kg has been distributed in 3 bags in the ratio 2:3:7

Let the small bag contains = 2x

Let the medium bag contains = 3x

Let the big bag contains = 7x

so the equation becomes

2x+3x+7x = 90

12x = 90

x = 90/12

x = 7.5

Thus,

Sand in small bag = 2x = 2(7.5) = 15 kg

Sand in medium bag = 3x = 3(7.5) = 22.5 kg

Sand in a large bag = 7x = 7(7.5) = 52.5 kg

<u>SOLUTION CHECK</u>

15+22.5+52.5=90 kg

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3 years ago

Sabrina rides her bike 2 miles to school each day she leaves her house 7:30 and arrives at 7:50 What is Sabrina's average speed

MakcuM [25]

6 mph.

To find this, create a ratio.

2/20 = x/60

This will allow you to compare here time of twenty minutes to an hour in the same context.

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Thus, Sabrina's average speed in miles per hour is six miles per hour.

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2 years ago

Zappos is an online retailer based in Nevada and employs 1,300 employees. One of their competitors, Amazon, would like to test t

Amanda [17]

Answer:

$t=\frac{33.9-36}{\frac{4.1}{\sqrt{22}}}=-2.402$

$df = n-1= 22-1=21$

$t_{\alpha/2}= -2.08$

Since the calculated values is lower than the critical value we have enough evidence to reject the null hypothesis at the significance level of 2.5% and we can say that the true mean is lower than 36 years old

Step-by-step explanation:

Data given

$\bar X=33.9$ represent the sample mean

$s=4.1$ represent the sample standard deviation

$n=22$ sample size

$\mu_o =26$ represent the value that we want to test

$\alpha=0.025$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

System of hypothesis

We need to conduct a hypothesis in order to check if the true mean is less than 36 years old, the system of hypothesis would be:

Null hypothesis: $\mu \geq 36$

Alternative hypothesis: $\mu < 36$

The statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

And replacing we got:

$t=\frac{33.9-36}{\frac{4.1}{\sqrt{22}}}=-2.402$

Now we can calculate the critical value but first we need to find the degreed of freedom:

$df = n-1= 22-1=21$

So we need to find a critical value in the t distribution with df =21 who accumulates 0.025 of the area in the left and we got:

$t_{\alpha/2}= -2.08$

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3 years ago

What are the correct steps for solving the following equation: 5x - = 21

ololo11 [35]

Answer:

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Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

At a university, 60% of the 7,400 students are female. The student newspaper reports the results of a survey of a random sample

omeli [17]

Given Information:

Population mean = p = 60% = 0.60

Population size = N = 7400

Sample size = n = 50

Required Information:

Sample mean = μ = ?

standard deviation = σ = ?

Answer:

Sample mean = μ = 0.60

standard deviation = σ = 0.069

Step-by-step explanation:

We know from the central limit theorem, the sampling distribution is approximately normal as long as the expected number of successes and failures are equal or greater than 10

np ≥ 10

50*0.60 ≥ 10

30 ≥ 10 (satisfied)

n(1 - p) ≥ 10

50(1 - 0.60) ≥ 10

50(0.40) ≥ 10

20 ≥ 10 (satisfied)

The mean of the sampling distribution will be same as population mean that is

Sample mean = p = μ = 0.60

The standard deviation for this sampling distribution is given by

$\sigma = \sqrt{\frac{p(1-p)}{n} }$

Where p is the population mean that is proportion of female students and n is the sample size.

$\sigma = \sqrt{\frac{0.60(1-0.60)}{50} }\\\\\sigma = \sqrt{\frac{0.60(0.40)}{50} }\\\\\sigma = \sqrt{\frac{0.24}{50} }\\\\\sigma = \sqrt{0.0048} }\\\\\sigma = 0.069$

Therefore, the standard deviation of the sampling distribution is 0.069.

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2 years ago