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Maurinko [17]
3 years ago
15

Rewrite as a logarithmic equation. e^9=y

Mathematics
1 answer:
kolbaska11 [484]3 years ago
4 0
Log y=9.
e


Drop first and make it logs base.
Y sits beside it
And 9 becomes answer
Therefore e = certain #
And to the power (which is Y) will give you answer of 9

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Simplify<br><br> 1/2 + (3/8 - 1/8)^2
Mandarinka [93]
9/16

Decimal form - 0.5625

You welcome :)
8 0
2 years ago
F = uv/u + v make u the subject
never [62]

I'm assuming that you mean

\dfrac{uv}{u+v}

because if you meant

\dfrac{uv}{u}+v

then u would simplify and you couldn't make it the subject.

Under this assumption, we start with

F=\dfrac{uv}{u+v}

We multiply both sides by u+v

F(u+v)=uv

We expand the left hand side:

Fu+Fv=uv

We move all terms involving u to the left and all terms not involving u to the right:

Fu-uv=-Fv

We factor u on the left hand side:

u(F-v)=-Fv

We divide both sides by F-v

u=\dfrac{-Fv}{F-v}

3 0
3 years ago
16. Solve for "x".<br> a. 6<br> b. 100<br> c. 36
erastovalidia [21]

Answer:

A. 6

Step-by-step explanation:

Using the Pythagorean theorem which states that: <u>Hypotenus² = Opposite² + Adjacent²</u>

Where: hypotenus = 10, opposite = x, adjacent = 8

So:

{10}^{2}  =  {x}^{2}  +  {8}^{2}

Solving for x

100 =  {x}^{2}  + 64

Collect like terms to make x the subject of formula

100 - 64 =  {x}^{2} →36 =  {x}^{2}

36 =  {x}^{2} ⟹ {x}^{2}  = 36

square root both sides of the equation to find the value of x

\sqrt{ {x}^{2} }  =  \sqrt{36} →x = 6

Therefore: Option A is correct

5 0
1 year ago
Will mark as brainlist
lara [203]

Step-by-step explanation:

Tn=ar^(n-1)

r=-10/-5=2

a=-5

Tn=-5×(2)^(n-1)

Tn=-5•(2)^(n-1)

an=5•(2)^(n-1)

7 0
2 years ago
I need help someone look at the picture
Natalka [10]

Answer:

2

Step-by-step explanation:

The outlier here is greatly above all of the others, the mean is the sum of all of the numbers/the amount of numbers. So, if we exclude the outlier, the sum of all of the numbers would decrease

3 0
3 years ago
Read 2 more answers
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