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3 years ago

The perimeter of an object is the sum of its side lengths. For example, the

Mathematics

1 answer:

vivado [14]3 years ago

3 0

Answer:

5 inches

Step-by-step explanation:

23 - 10 - 8 = 5 inches

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Ivan used coordinate geometry to prove that quadrilateral EFGH is a square.

Thepotemich [5.8K]

Answer:

this is geometry?

Step-by-step explanation:

5 0

3 years ago

A cylindrical soup can has a diameter of 3.6 in. and is 6.4 in. tall. Find the volume of the can.

arsen [322]

<h2>⚘Your Answer:------</h2>

<h3>Given Information:</h3>

Diameter of can:- 3.6 cm
Height of can:- 6.4 cm

Volume of the Can.

<h3>Solution:</h3>

Radius = (Diameter/2)

ㅤㅤㅤㅤ3.6 cm/2

ㅤㅤㅤㅤ1.8 cm

So, Radius of the soup can is 1.8 cm.

Volume øf cylinder = Volume øf can

Volume of cylinder = π r²h

(π = 22/7)

(r = radius = 1.8 cm)

(h = height = 6.4 cm

ㅤㅤㅤㅤㅤㅤㅤㅤㅤ= 22/7×(1.8 cm)²× 6.4 cm

ㅤㅤㅤㅤㅤㅤㅤㅤㅤ= 22/7× 3.24 cm² × 6.4 cm

ㅤㅤㅤㅤㅤㅤㅤㅤㅤ= 22/7 × 20.736 cm³

ㅤㅤㅤㅤㅤㅤㅤㅤㅤ= (456.192/7) cm³

ㅤㅤㅤㅤㅤㅤㅤㅤㅤ= 65.17 cm³

So, the Volume of the soup can is 65.17 cm³

ㅤㅤㅤㅤㅤㅤㅤㅤ⚘Thank You

7 0

2 years ago

How do I solve by using system of elimination?

Nikitich [7]

You eliminate or ‘take away’ the answers that you know or think that r wrong. The last answer that’s left is your answer.

6 0

3 years ago

Suppose after 2500 years an initial amount of 1000 grams of a radioactive substance has decayed to 75 grams. What is the half-li

krok68 [10]

Answer:

The correct answer is:

Between 600 and 700 years (B)

Step-by-step explanation:

At a constant decay rate, the half-life of a radioactive substance is the time taken for the substance to decay to half of its original mass. The formula for radioactive exponential decay is given by:

$A(t) = A_0 e^{(kt)}\\where:\\A(t) = Amount\ left\ at\ time\ (t) = 75\ grams\\A_0 = initial\ amount = 1000\ grams\\k = decay\ constant\\t = time\ of\ decay = 2500\ years$

First, let us calculate the decay constant (k)

$75 = 1000 e^{(k2500)}\\dividing\ both\ sides\ by\ 1000\\0.075 = e^{(2500k)}\\taking\ natural\ logarithm\ of\ both\ sides\\In 0.075 = In (e^{2500k})\\In 0.075 = 2500k\\k = \frac{In0.075}{2500}\\ k = \frac{-2.5903}{2500} \\k = - 0.001036$

Next, let us calculate the half-life as follows:

$\frac{1}{2} A_0 = A_0 e^{(-0.001036t)}\\Dividing\ both\ sides\ by\ A_0\\ \frac{1}{2} = e^{-0.001036t}\\taking\ natural\ logarithm\ of\ both\ sides\\In(0.5) = In (e^{-0.001036t})\\-0.6931 = -0.001036t\\t = \frac{-0.6931}{-0.001036} \\t = 669.02 years\\\therefore t\frac{1}{2} \approx 669\ years$

Therefore the half-life is between 600 and 700 years

5 0

3 years ago

Plz help me solve these problems

leva [86]

Answer: CAN YOU PLS MARK AS BRAINLIEST??

a.x=11/4

b.x=6

c.x=21/2

d.x=0

Step-by-step explanation:

-2+3x+x=9-x

-2+3x+x=9

4x=9+2

4x=11

x=11/4

when you move a numerator to the other side it becomes a denominator

x+2=3/4x6

x+2=3/24

x=8-2

x=6

5-2x-12=14

2x=14-5+12

2x=21

x=21/2

1/2x=-3-1/2x+4-1

1/2x+1/2x=-3+4-1

x=0

6 0

3 years ago