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Sonja [21]
3 years ago
9

Which color uses the most wrapping paper​

Mathematics
1 answer:
choli [55]3 years ago
8 0

Answer: I'm pretty sure its the green rectangle

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Select the correct locations on each number line.
alexandr402 [8]

Answer:

girl joi for help all

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4 0
3 years ago
Find the surface area of the ball shown to the right <br><br> d=20
netineya [11]

Answer:

<h3>Surface Area = 1,256 cm</h3>

<u>Solution:</u>

formula: Surface Area of a Sphere: 4π · r²

Surface area = 4π · r²

SA = 4(3.14) (10)²

SA =  (12.56)(100)

SA = 1,256

7 0
3 years ago
In a right triangle ABC, CD is an altitude, such that AD=BC. Find AC, if AB=3 cm, and CD= 2 cm.
konstantin123 [22]

Consider right triangle ΔABC with legs AC and BC and hypotenuse AB. Draw the altitude CD.

1. Theorem: The length of each leg of a right triangle is the geometric mean of the length of the hypotenuse and the length of the segment of the hypotenuse adjacent to that leg.

According to this theorem,

BC^2=BD\cdot AB.

Let BC=x cm, then AD=BC=x cm and BD=AB-AD=3-x cm. Then

x^2=(3-x)\cdot 3,\\ \\x^2=9-3x,\\ \\x^2+3x-9=0,\\ \\D=3^2-4\cdot (-9)=9+36=45,\\ \\\sqrt{D}=\sqrt{45}=3\sqrt{5},\\ \\x_1=\dfrac{-3-3\sqrt{5} }{2}0.

Take positive value x. You get

AD=BC=\dfrac{-3+3\sqrt{5} }{2}\ cm.

2. According to the previous theorem,

AC^2=AD\cdot AB.

Then

AC^2=\dfrac{-3+3\sqrt{5} }{2}\cdot 3=\dfrac{-9+9\sqrt{5} }{2},\\ \\AC=\sqrt{\dfrac{-9+9\sqrt{5} }{2}}\ cm.

Answer: AC=\sqrt{\dfrac{-9+9\sqrt{5} }{2}}\ cm.

This solution doesn't need CD=2 cm. Note that if AB=3cm and CD=2cm, then

CD^2=AD\cdot DB,\\ \\2^2=AD\cdot (3-AD),\\ \\AD^2-3AD+4=0,\\ \\D

This means that you cannot find solutions of this equation. Then CD≠2 cm.

8 0
3 years ago
Read 2 more answers
Help me plz I need this quick
Lena [83]

I think it will be neither.

4 0
3 years ago
Read 2 more answers
PLS HELP!!
GuDViN [60]
25.69 + .75= $26.44

Hope this helps.
7 0
3 years ago
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