I will help, what is your book called?
The answer for this problem i −10x2+66xy−36y2−5x+3y
Let's solve it by step by step.
(−5x+3y)(2x−12y+1)
=(−5x+3y)(2x+−12y+1)
=(−5x)(2x)+(−5x)(−12y)+(−5x)(1)+(3y)(2x)+(3y)(−12y)+(3y)(1)
=−10x2+60xy−5x+6xy−36y2+3y
So, -10x2+66xy-36y2-5x+3y
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Answer:
4x - 6y
Step-by-step explanation:
Answer:
Step-by-step explanation:
We need to solve 
We know that,
Using the above formula,
![(8m-3n)^2 - (4m+3n)^2=(8m)^2+(3n)^2-2(8m)(3n)-[(4m)^2+(3n)^2+2(4m)(3n)]\\\\=64m^2+9n^2-48mn-(16m^2+9n^2+24mn)\\\\=64m^2+9n^2-48mn-16m^2-9n^2-24mn\\\\=48m^2-48mn-24mn\\\\=48m^2-72mn](https://tex.z-dn.net/?f=%288m-3n%29%5E2%20-%20%284m%2B3n%29%5E2%3D%288m%29%5E2%2B%283n%29%5E2-2%288m%29%283n%29-%5B%284m%29%5E2%2B%283n%29%5E2%2B2%284m%29%283n%29%5D%5C%5C%5C%5C%3D64m%5E2%2B9n%5E2-48mn-%2816m%5E2%2B9n%5E2%2B24mn%29%5C%5C%5C%5C%3D64m%5E2%2B9n%5E2-48mn-16m%5E2-9n%5E2-24mn%5C%5C%5C%5C%3D48m%5E2-48mn-24mn%5C%5C%5C%5C%3D48m%5E2-72mn)
So, the final answer is .
Answer:
9% probability that Jim will be accepted at both universities
Step-by-step explanation:
We have these following probabilities:
A 20% probability that Jim is accepted into the University X.
A 45% probability that Jim is accepted into the University Y.
What is the probability that Jim will be accepted at both universities?
It is the multiplication of both these probabilities
So there is a 0*2*0.45 = 0.09 = 9% probability that Jim will be accepted at both universities
