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1 year ago

8

You ping a host on the internet to check for connectivity. Your ping times out, and you get no response. What is most likely the

cause of this?

Computers and Technology

1 answer:

Reptile [31]1 year ago

8 0

Answer:

It could be because you where hack. Or there was something wrong with the site that stopped it from saying why it stopped.

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Consider a set of mobile computing clients in a certain town who each

poizon [28]

Answer: answer given in the explanation

Explanation:

We have n clients and k-base stations, say each client has to be connected to a base station that is located at a distance say 'r'. now the base stations doesn't have allocation for more than L clients.

To begin, let us produce a network which consists of edges and vertex

Network (N) = (V,E)

where V = [S, cl-l, - - - - cl-n, bs-l - - - - - - bs-k, t]

given that cl-l, - - - - - cl-n represents nodes for the clients

also we have that bs-l, - - - - - bs-k represents the nodes for base station

Also

E = [ (s, cl-i), (cl-i,bs-j), (bs-j,t)]

(s, cl-i) = have capacity for all cl-i (clients)

(cl-i,bs-j) = have capacity for all cl-i clients & bs-j (stations)

⇒ using Fond Fulkorson algorithm we find the max flow in N

⇒ connecting cl-i clients to bs-j stations

like (cl-i, bs-j) = 1

if f(cl-i, bs-j) = 0

⇒ say any connection were to produce a valid flow, then

if cl-i (clients) connected f(s,cl-i) = 1 (o otherwise)

if cl-i (clients) connected to bs-j(stations) f(cl-i,bs-j) = 1 (o otherwise)

f(bs-j,t) = no of clients (cl-i) connected to bs-j

⇒ on each node, the max flow value (f) is longer than the no of clients that can be connected.

⇒ create the connection between the client and base station i.e. cl-l to base bs-j iff f(cl-i, bs-j) = 1

⇒ when considering the capacity, we see that any client cannot directly connect to the base stations, and also the base stations cannot handle more than L clients, that is because the load allocated to the base statsion is L.

from this, we say f is the max no of clients (cl-i) that can be connected if we find the max flow, we can thus connect the client to the base stations easily.

cheers i hope this helps

5 0

2 years ago

Which of these options highlights the need for learning algorithms

LiRa [457]

Answer: D.

Explanation:

7 0

2 years ago

Read 2 more answers

a cryptarithm is a mathematical puzzle where the goal is to find the correspondence between letters and digits such that the giv

Leokris [45]

Using the knowledge in computational language in C++ it is possible to write a code that cryptarithm is a mathematical puzzle where the goal is to find the correspondence between letters and digits

<h3>Writting the code:</h3>

<em>#include <bits/stdc++.h></em>

<em>using namespace std;</em>

<em>// chracter to digit mapping, and the inverse</em>

<em>// (if you want better performance: use array instead of unordered_map)</em>

<em>unordered_map<char, int> c2i;</em>

<em>unordered_map<int, char> i2c;</em>

<em>int ans = 0;</em>

<em>// limit: length of result</em>

<em>int limit = 0;</em>

<em>// digit: index of digit in a word, widx: index of a word in word list, sum: summation of all word[digit] </em>

<em>bool helper(vector<string>& words, string& result, int digit, int widx, int sum) { </em>

<em> if (digit == limit) {</em>

<em> ans += (sum == 0);</em>

<em> return sum == 0;</em>

<em> }</em>

<em> // if summation at digit position complete, validate it with result[digit].</em>

<em> if (widx == words.size()) {</em>

<em> if (c2i.count(result[digit]) == 0 && i2c.count(sum%10) == 0) {</em>

<em> if (sum%10 == 0 && digit+1 == limit) // Avoid leading zero in result</em>

<em> return false;</em>

<em> c2i[result[digit]] = sum % 10;</em>

<em> i2c[sum%10] = result[digit];</em>

<em> bool tmp = helper(words, result, digit+1, 0, sum/10);</em>

<em> c2i.erase(result[digit]);</em>

<em> i2c.erase(sum%10);</em>

<em> ans += tmp;</em>

<em> return tmp;</em>

<em> } else if (c2i.count(result[digit]) && c2i[result[digit]] == sum % 10){</em>

<em> if (digit + 1 == limit && 0 == c2i[result[digit]]) {</em>

<em> return false;</em>

<em> }</em>

<em> return helper(words, result, digit+1, 0, sum/10);</em>

<em> } else {</em>

<em> return false;</em>

<em> }</em>

<em> }</em>

<em> // if word[widx] length less than digit, ignore and go to next word</em>

<em> if (digit >= words[widx].length()) {</em>

<em> return helper(words, result, digit, widx+1, sum);</em>

<em> }</em>

<em> // if word[widx][digit] already mapped to a value</em>

<em> if (c2i.count(words[widx][digit])) {</em>

<em> if (digit+1 == words[widx].length() && words[widx].length() > 1 && c2i[words[widx][digit]] == 0) </em>

<em> return false;</em>

<em> return helper(words, result, digit, widx+1, sum+c2i[words[widx][digit]]);</em>

<em> }</em>

<em> // if word[widx][digit] not mapped to a value yet</em>

<em> for (int i = 0; i < 10; i++) {</em>

<em> if (digit+1 == words[widx].length() && i == 0 && words[widx].length() > 1) continue;</em>

<em> if (i2c.count(i)) continue;</em>

<em> c2i[words[widx][digit]] = i;</em>

<em> i2c[i] = words[widx][digit];</em>

<em> bool tmp = helper(words, result, digit, widx+1, sum+i);</em>

<em> c2i.erase(words[widx][digit]);</em>

<em> i2c.erase(i);</em>

<em> }</em>

<em> return false;</em>

<em>}</em>

<em>void isSolvable(vector<string>& words, string result) {</em>

<em> limit = result.length();</em>

<em> for (auto &w: words) </em>

<em> if (w.length() > limit) </em>

<em> return;</em>

<em> for (auto&w:words) </em>

<em> reverse(w.begin(), w.end());</em>

<em> reverse(result.begin(), result.end());</em>

<em> int aa = helper(words, result, 0, 0, 0);</em>

<em>}</em>

<em />

<em>int main()</em>

<em>{</em>

<em> ans = 0;</em>

<em> vector<string> words={"GREEN" , "BLUE"} ;</em>

<em> string result = "BLACK";</em>

<em> isSolvable(words, result);</em>

<em> cout << ans << "\n";</em>

<em> return 0;</em>

<em>}</em>

See more about C++ code at brainly.com/question/19705654

#SPJ1

3 0

1 year ago

You have a manager who makes decisions without getting input from anyone. They are unwilling to change anything once a decision

saw5 [17]

Answer:

autocratic

Explanation:

taking no account of other peoples wishes or opinions; domineering

3 0

2 years ago

In the Budget Details sheet, if you wish to autofill with the formula, you must use a ______ reference for the LY Spend Total ce

ahrayia [7]

Answer:

The answer is A.Absolute reference.

Explanation:

Absolute reference is a cell reference whose location remains constant when the formula is copied.

8 0

3 years ago