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ikadub [295]
2 years ago
15

I NEED HELPPP WITH THISSS

Mathematics
2 answers:
Vladimir79 [104]2 years ago
5 0

Answer:

the answer is a

Step-by-step explanation:

mark me as brainliest

goblinko [34]2 years ago
3 0

Answer:

\boxed{\boxed{\sf (-20) }}

given - X = (-8).

  • Y = 7
  • Z = (-11)

To find - Value of this equation

Solution-

(-13) -Y

putting the value of y = 7 in the equation

(-13) -7

-20

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Answer:

Directrix

Step-by-step explanation:

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3 years ago
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weeeeeb [17]
(5-3)^2 is = -4 , the second one is -9.67
4 0
3 years ago
Find the surface area of the figure below:<br> ???
Ulleksa [173]

Answer:

85 ft^2

Step-by-step explanation:

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3 years ago
Correctly describe the slope of the graph of 2x + 5y = 6?
USPshnik [31]

Answer:

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ok

6 0
3 years ago
I need to find all real values of x from this inequality x^2&gt;2x-2 and also this question x^2&gt;2x+2. I need the answer fast
sergeinik [125]

x^2\gt2x-2

x^2-2x+2\gt0

You are essentially asking at this point where is the quadratic function greater than 0. To get the interval find the roots. Between the roots the function is guaranteed to be LESS THAN zero. Everywhere else the function is greater than 0.

x^2-2x+2=0

Use Vieta's rule to get the roots,

(x-1)(x-1)=0

Both roots are the same so no value is less than 0 which means all values except at the point of root are strictly greater, the point of root is at x_{1,2}=1 which means the set for which the quadratic function is greater than 0 is \mathbb{R}-\{1\} "all real numbers except 1".

To convert this into interval notation use all numbers up to 1 but not including and all numbers after 1 but not including,

(-\infty,1)\cup(1,\infty)

Hope this helps :)

7 0
3 years ago
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