Big-O notation is a way to describe a function that represents the n amount of times a program/function needs to be executed.
(I'm assuming that := is a typo and you mean just =, by the way)
In your case, you have two loops, nested within each other, and both loop to n (inclusive, meaning, that you loop for when i or j is equal to n), and both loops iterate by 1 each loop.
This means that both loops will therefore execute an n amount of times. Now, if the loops were NOT nested, our big-O would be O(2n), because 2 loops would run an n amount of times.
HOWEVER, since the j-loop is nested within i-loop, the j-loop executes every time the i-loop <span>ITERATES.
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As previously mentioned, for every i-loop, there would be an n amount of executions. So if the i-loop is called an n amount of times by the j loop (which executes n times), the big-O notation would be O(n*n), or O(n^2).
(tl;dr) In basic, it is O(n^2) because the loops are nested, meaning that the i-loop would be called n times, and for each iteration, it would call the j-loop n times, resulting in n*n runs.
A way to verify this is to write and test program the above. I sometimes find it easier to wrap my head around concepts after testing them myself.
Specify the tempo of a song
Answer:
A) The risk/return Tradeoff is applicable to speculative risks.
Explanation:
Speculative risk always has a positive payoff and also a negative payoff , so option (b) is incorrect.
Speculative risk is a source of great concern for risk managers, so option (c)is incorrect.
Speculative risk is a category of risk that can be taken on voluntarily and will either result in a profit or loss , so option d is wrong
Pure risk, also called absolute risk, is a category of threat that is beyond human control and has only one possible outcome if it occurs: loss. Pure risk includes such incidents as natural disasters, fire or untimely death. so option (e) also incorrect
The answer is B. A collection of mainstream sources of information.
