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Temka [501]
3 years ago
8

Convert each of the following base 10 & base 2 numbers in signed magnitude, one’s complement and two’s complement. Each of t

he numbers should be represented in 8 bits. a) 43 b)-43 c)011110
Computers and Technology
1 answer:
asambeis [7]3 years ago
7 0

011110 is the following base 10 & base 2 numbers in signed magnitude, one’s complement and two’s complement.

c)011110

<u>Explanation:</u>

Converting 10 base signed number as two complements. In computer signed is maintain in registered.

But computer needs all values in bits. In hardware it is considered as on or off methods. ASCII values are converted into bits and executed by CPU.

All values which been entered in computer are taken respective ASCII values and converted to bits. Normally sign symbol are maintained as registered flag which can be know if end user knows assembly programming languages.

Assembly language by which direct interacted with machine languages and faster in executions.

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Answer:

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3 years ago
Timothy is a multimedia designer. He needs to create a prototype of a new product that his firm is launching. Which multimedia s
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Explanation:

The answer is D. 3-f modeling

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Write a Scheme function called "sum" which takes an input function func and a nonnegative number n and outputs the value
solong [7]

Answer:

function sum(number) {

      if (number == 1) {

             return 1;

      }

      return number + sum(number -1);

}

Explanation:

This is a recursive function, it means that is a function that calls itself for example: if you call the function with sum(5) the process is :

sum(5)

   |______ 5 + sum(4)

                           |_______ 4 + sum(3)

                                                       |______ 3 + sum(2)

                                                                                   |_____2 + sum(1)

                                                                                                        |_____ 1

                                                                                                 

the result is 1+2+3+4+5 = 15

7 0
3 years ago
Instructions The population of town A is less than the population of town B. However, the population of town A is growing faster
weeeeeb [17]

Answer: The c++ program is given below.

#include <iostream>

using namespace std;

int main() {

float townA, townB, growthA, growthB, populationA, populationB;

    int year=0;    

cout<<"Enter present population of town A : ";

cin >> townA;  

cout<<endl<<"Enter present growth rate of town A : ";

cin >> growthA;

growthA = growthA/100;  

cout<<endl<<"Enter present population of town B : ";

cin >> townB;  

cout<<endl<<"Enter present growth rate of town B : ";

cin >> growthB;

growthB = growthB/100;  

do

{

    populationA = townA + (townA * growthA);

    populationB = townB + (townB * growthB);      

    townA = populationA;

    townB = populationB;      

    year++;      

}while(populationA < populationB);  

cout<<endl<<"After " <<year<< " years, population of town A is "<<populationA << " and population of town B is "<< population<<endl;

return 0;

}

Explanation:

All the variables for population and growth rate are declared with float datatype.

The user inputs the present population of both the towns.

The growth rate entered by the user is the percentage growth.

For example, town A has 10% growth rate as shown in the output image.

The program converts 10% into float as 10/100.

growthA = growthA/100;

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The above conversion is done to ease the calculations.

The year variable is declared as integer and initialized to 0.

The growth in population is computed in a do-while loop. After each growth is calculated, the year variable is incremented by 1.

The loop continues until population of town A becomes greater than or equal to population of town B as mentioned in the question.

Once the loop discontinues, the final populations of town A and town B and the years needed for this growth is displayed.

The new line is introduced using endl keyword.

The function main has return type int hence, 0 is returned at the end of the program.

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