Answer:
304/3
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Step-by-step explanation:
<u>Step 1: Define</u>
3x² - 4(2y - 4/12) + 8
x = 6, y = 2
<u>Step 2: Evaluate</u>
- Substitute in variables: 3(6)² - 4(2(2) - 4/12) + 8
- Evaluate exponents: 3(36) - 4(2(2) - 4/12) + 8
- Multiply: 108 - 4(2(2) - 4/12) + 8
- (Parenthesis) Multiply: 108 - 4(4 - 4/12) + 8
- (Parenthesis - Fraction) Simplify: 108 - 4(4 - 1/3) + 8
- (Parenthesis) Subtract: 108 - 4(11/3) + 8
- Multiply: 108 - 44/3 + 8
- Subtract: 280/3 + 8
- Add: 304/3
The answer to this question is $42
Answer:
The answer is -22x² - 14x.
Step-by-step explanation:
You have to eliminate the brackets by multiplying :
![2x( - 11x - 7)](https://tex.z-dn.net/?f=2x%28%20-%2011x%20-%207%29)
![= 2x( - 11x) + 2x( - 7)](https://tex.z-dn.net/?f=%20%3D%202x%28%20-%2011x%29%20%2B%202x%28%20-%207%29)
![= - 22 {x}^{2} - 14x](https://tex.z-dn.net/?f=%20%3D%20%20-%2022%20%7Bx%7D%5E%7B2%7D%20%20-%2014x)
Next you can simplify but there is no common terms in this expression so it remains the same.
Answer:I would be scared especially since it’s ramadan
Step-by-step explanation:
Answer:
- sin = √(1 -cos²)
- tan = (√(1 -cos²))/cos
Step-by-step explanation:
![\displaystyle\sin^2{\theta}+\cos^2{\theta}=1 \qquad\text{Pythagorean identiy}\\\\\sin{\theta}=\sqrt{1-\cos^2{\theta}} \qquad\text{solved for sine}\\\\\tan{\theta}=\frac{\sin{\theta}}{\cos{\theta}}=\frac{\sqrt{1-\cos^2{\theta}}}{\cos{\theta}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Csin%5E2%7B%5Ctheta%7D%2B%5Ccos%5E2%7B%5Ctheta%7D%3D1%20%5Cqquad%5Ctext%7BPythagorean%20identiy%7D%5C%5C%5C%5C%5Csin%7B%5Ctheta%7D%3D%5Csqrt%7B1-%5Ccos%5E2%7B%5Ctheta%7D%7D%20%5Cqquad%5Ctext%7Bsolved%20for%20sine%7D%5C%5C%5C%5C%5Ctan%7B%5Ctheta%7D%3D%5Cfrac%7B%5Csin%7B%5Ctheta%7D%7D%7B%5Ccos%7B%5Ctheta%7D%7D%3D%5Cfrac%7B%5Csqrt%7B1-%5Ccos%5E2%7B%5Ctheta%7D%7D%7D%7B%5Ccos%7B%5Ctheta%7D%7D)
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If you draw a triangle with a hypotenuse of 1 and an "adjacent" leg of "cos", then using the Pythagorean theorem, you can see that the "opposite" leg will be √(1-cos²) and the tangent will be (√(1-cos²))/cos. Whether or not you're allowed to draw such a triangle on paper, you can certainly do it in your mind.