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NeX [460]
3 years ago
11

Write a polynomial functionſ of least degree that has rational coefficients, a leading coefficient of 1, and the zeros 1,3, and

Mathematics
1 answer:
otez555 [7]3 years ago
8 0

Answer:

f(x) = x^{4}  -  8x^{3}  + 24x^{2}  - 32x  + 15

Step-by-step explanation:

First of all, if 2 - i is a zero, then so is 2 + i

All you need to do now is multiply (x - 1)(x - 3)(x - 2 + i)(x - 2 - i)

I will do part of that multiplication

(x - 2 + i)(x - 2 - i) = x^{2} - 2x - xi - 2x + 4 + 2i + xi - 2i - i^{2}

                           = x^{2} - 4x + 5

So, now (x - 1)(x - 3)(x^{2} - 4x + 5) =  x^{4}  -  8x^{3}  + 24x^{2}  - 32x  + 15

I will let you finish that multiplication.  I did some and you can do some.  OK?

                                     

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Answer:

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Because the product is 0, either (x-1) or (x-7) is equal to 0. That means that x = 1, or 7

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3 years ago
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Answer:

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