Answer:
25
![( \sqrt{5})( \sqrt{5} ) \\ \sqrt{5 \times 5} \\ \sqrt{25} \\ 5](https://tex.z-dn.net/?f=%28%20%5Csqrt%7B5%7D%29%28%20%5Csqrt%7B5%7D%20%20%29%20%5C%5C%20%20%5Csqrt%7B5%20%5Ctimes%205%7D%20%20%5C%5C%20%20%5Csqrt%7B25%7D%20%20%5C%5C%205)
so x= 25
25=tex]( \sqrt{5})( \sqrt{5})
hope it's helpful ❤❤❤❤
THANK YOU.
Answer:
the number of student that took the test is missing
I think it is 100?
79 is 1 sigms (1 standard deviation) above the mean....
1 sd is 84% ... 16% are above the 79
multiply the students that took the test by .16
Step-by-step explanation:
Answer: 22
Step-by-step explanation:
11 - 6 = 5
4 x 5 = 20
20 + 2 = 22
' pls can i have brainliest? i need it for my goal'
Answer:
9·x² - 36·x = 4·y² + 24·y + 36 in standard form is;
(x - 2)²/2² - (y + 3)²/3² = 1
Step-by-step explanation:
The standard form of a hyperbola is given as follows;
(x - h)²/a² - (y - k)²/b² = 1 or (y - k)²/b² - (x - h)²/a² = 1
The given equation is presented as follows;
9·x² - 36·x = 4·y² + 24·y + 36
By completing the square, we get;
(3·x - 6)·(3·x - 6) - 36 = (2·y + 6)·(2·y + 6)
(3·x - 6)² - 36 = (2·y + 6)²
(3·x - 6)² - (2·y + 6)² = 36
(3·x - 6)²/36 - (2·y + 6)²/36 = 36/36 = 1
(3·x - 6)²/6² - (2·y + 6)²/6² = 1
3²·(x - 2)²/6² - 2²·(y + 3)²/6² = 1
(x - 2)²/2² - (y + 3)²/3² = 1
The equation of the hyperbola is (x - 2)²/2² - (y + 3)²/3² = 1.
So y=mx+b form
m=slope=rise over run
b=y intercepe or where it crosses the y axis
so one way is to input values for x and get vales for y exg
if x=1 then y=-2
if x=2 then y=1
if x=0 then y=-5 so some points are
(x,y)
(1,2)
(2,1)
(0,-5)
(3,4)
then plot those points