6(-2+8b)+2b -12+48b+2b 50b-12
Answer:
25020, 25920, 25425
Step-by-step explanation:
To find if our number is divisible by 5 the number must end with 0 or 5, divisibility by 9 is if sum of all numbers in number is divisible by 9,
We know B must end with 0 or 5
1. Case 25A20 sum of that number is 9 so if we pick 0 as A we have first number because 9/9=1
We can put A as 9 because 18/9=2
2. Case B = 0, sum is 14 so we need pick A as 4 to get 18.
Let thw second integer be x
then the first = 2x
and the third integer is = 6+x
their sum = 74
x+2x+6+x = 74
4x +6 = 74
4x = 74-6 =68
x =68÷4
x = 17
then the first integer is 2×17 = 34
the third integer is 17+6 = 23
the integers are 17 , 23 and 34
61/100 = 0.61
so
the least is 61/100 then 0.65 and then 61.5 last
Answer:
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