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Westkost [7]
3 years ago
6

Simplify the expression by adding or subtracting the linear expressions. 7x + 9x + 8 + 4x + 5 *

Mathematics
1 answer:
Lady_Fox [76]3 years ago
4 0

Answer:

A

Step-by-step explanation:

7x+9x+4x+8+5=20x+13

20+13.

Hope this helps :D

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olchik [2.2K]
It’s 4/3. Count up 4 and go over 3.
3 0
3 years ago
Use the Distributive Property to multiply. –5(2x – 5)\
Basile [38]

Answer:

-10x +25

Step-by-step explanation:

–5(2x – 5)

Distribute

-5 * 2x - (-5) * 5

-10x +25

4 0
3 years ago
Read 2 more answers
Exclude leap years from the following calculations. ​(a) Compute the probability that a randomly selected person does not have a
Scrat [10]

Answer:

a) 99.73% probability that a randomly selected person does not have a birthday on March 14.

b) 96.71% probability that a randomly selected person does not have a birthday on the 2 nd day of a month.

c) 98.08% probability that a randomly selected person does not have a birthday on the 31 st day of a month.

d) 92.33% probability that a randomly selected person was not born in February.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

A non-leap year has 365 days.

​(a) Compute the probability that a randomly selected person does not have a birthday on March 14.

There are 365-1 = 364 days that are not March 14. So

364/365 = 0.9973

99.73% probability that a randomly selected person does not have a birthday on March 14.

​(b) Compute the probability that a randomly selected person does not have a birthday on the 2 nd day of a month.

There are 12 months, so there are 12 2nds of a month.

So

(365-12)/365 = 0.9671

96.71% probability that a randomly selected person does not have a birthday on the 2 nd day of a month.

​(c) Compute the probability that a randomly selected person does not have a birthday on the 31 st day of a month.

The following months have 31 days: January, March, May, July, August, October, December.

So there are 7 31st days of a month during a year.

Then

(365-7)/365 = 0.9808

98.08% probability that a randomly selected person does not have a birthday on the 31 st day of a month.

(d) Compute the probability that a randomly selected person was not born in February.

During a non-leap year, February has 28 days. So

(365-28)/365 = 0.9233

92.33% probability that a randomly selected person was not born in February.

6 0
3 years ago
Select the correct answer. Which of the following is equal to the expression below? (8 - 320) 3 OA. 40 O B. 30 OC. 10 5 OD. 835​
ra1l [238]

Answer:

Quesiton is not clear. here is the asnswer basing on our understand

Step-by-step explanation:

(8-32)3 = (-24*3) = =72

3 0
3 years ago
 Use what you've learned in this unit to model the population of Western
azamat

The population function of the Western Lowland Gorillas can either represent population growth or population decay

<h3>How to model the population</h3>

The question is incomplete, as the resources to model the population of the Western Lowland Gorillas are not given.

So, I will give a general explanation to solve the question

A population function can be represented as:

y = a(1 \pm r)^x

Where:

  • The initial population of the Western Lowland Gorillas is represented by (a)
  • The rate at which the population changes is represented by (r)
  • The number of years since 2022 is represented by (x)
  • The population in x years is represented by (y)

From the question, we understand that the population of the Western Lowland Gorillas decreases.

This means that the rate of the function would be an exponential decay i.e. 1 -r

Take for instance:

y = 2000 * 0.98^x

By comparison.

a = 2000 and 1 - r = 0.98

The above function can be used to model the population of the Western Lowland Gorillas

Read more about exponential functions at:

brainly.com/question/26829092

4 0
2 years ago
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