Answer:cost of each pound of apple= $3
And cost of each pound of orange =$2
Step-by-step explanation:
Step 1
Let cost of apples = x
And cost of Oranges =y
Let 6 pounds of apples and 3 pounds of oranges cost 24 dollars be represented as
6 x + 3y= 24----- equation 1
Also, Let 5 pounds of apples and 4 pounds of oranges cost 23 dollars be represented as
5x+ 4y= 23----- equation 2
Step 2
6 x + 3y= 24----- equation 1
5x+ 4y= 23----- equation 2
Using substitution method to solve the equation
6 x + 3y= 24
24-6x=3y
y= 24-6x/3 = 8-2x
Y= 8-2x
Substituting the value of y= 8-2x into equation 2
5x+ 4( 8-2x)= 23
5x+ 32 -8x= 23
32-23= 8x-5x
9=3x
x=9/3
x=3
Putting the value of x= 3 in equation 1 and solving to find y
6 x + 3y= 24
6(3) +3y= 24
18+3y=24
3y= 24-18
3y=6
y=6/3= 2
Therefore the cost of each pound of apple= $3
And cost of each pound of orange =$2
Answer:
1.
4/8/9
4*9/8
9/2
2.
2/5/6
2*6/5
12/5
3.
4/1/4
4*4
16
4.
2/1/4
2*4
8
5.
3/1/7
3*7
21
The answer isw c because when i first looked at it i was like its a then i soveled the problem out
