All categories

2 years ago

Please help me ... 6a + 2(c - b) when a = 2, b = 1, and c = 9 I know thë answer but I just need an explanation

Mathematics

1 answer:

Angelina_Jolie [31]2 years ago

5 0

Answer:

Step-by-step explanation:

Let the expression representing a situation is,

y = 6a + 2(c - b)

Where, a, b and c are the constants

If a = 2, b = 1 and c = 9

By substituting these values in the expression,

y = 6(2) + 2(9 - 1)

y = 12 + 16

y = 28

Therefore, for all given values of the constants value of y is 28.

You might be interested in

Let a and b be roots of x² - 4x + 2 = 0. find the value of a/b² +b/a²

erastovalidia [21]

Answer:

$\dfrac{a}{b^2}+\dfrac{b}{a^2}=10$

Step-by-step explanation:

Given equation: $x^2-4x+2=0$

The roots of the given quadratic equation are the values of x when $y=0$ .

To find the roots, use the quadratic formula:

$x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\quad\textsf{when }\:ax^2+bx+c=0$

Therefore:

$a=1, \quad b=-4, \quad c=2$

$\begin{aligned}\implies x & =\dfrac{-(-4) \pm \sqrt{(-4)^2-4(1)(2)}}{2(1)}\\& =\dfrac{4 \pm \sqrt{8}}{2}\\& =\dfrac{4 \pm 2\sqrt{2}}{2}\\& =2 \pm \sqrt{2}\end{aligned}$

$\textsf{Let }a=2+\sqrt{2}$

$\textsf{Let }b=2-\sqrt{2}$

Therefore:

$\begin{aligned}\implies \dfrac{a}{b^2}+\dfrac{b}{a^2} & = \dfrac{2+\sqrt{2}}{(2-\sqrt{2})^2}+\dfrac{2-\sqrt{2}}{(2+\sqrt{2})^2}\\\\& = \dfrac{2+\sqrt{2}}{6-4\sqrt{2}}+\dfrac{2-\sqrt{2}}{6+4\sqrt{2}}\\\\& = \dfrac{(2+\sqrt{2})(6+4\sqrt{2})+(2-\sqrt{2})(6-4\sqrt{2})}{(6-4\sqrt{2})(6+4\sqrt{2})}\\\\& = \dfrac{12+8\sqrt{2}+6\sqrt{2}+8+12-8\sqrt{2}-6\sqrt{2}+8}{36+24\sqrt{2}-24\sqrt{2}-32}\\\\& = \dfrac{40}{4}\\\\& = 10\end{aligned}$

6 0

1 year ago

Read 2 more answers

Help me please!! I’m in a hurry!! 15pts!!

Nikolay [14]

Answer:

300 times

Step-by-step explanation:

6 0

2 years ago

In a translation, what math process is used? WILL GIVE BRAINILEST!!!

jekas [21]

The answer is B multiplication That’s correct who is the

3 0

2 years ago

Read 2 more answers

A lot of 100 semiconductor chips contains 15 that are defective. three chips are selected at random from the lot without replace

Alex787 [66]

D=event that chip selected is defective
d=event that chip selected is NOT defective

Four possible scenarios for the first two selections:
P(DDD)=15/100*14/99*13/98=13/4620
P(DdD)=15/100*85/99*14/98=17/924
P(dDD)=85/100*15/99*14/99=17/924
P(ddD)=85/100*84/99*15/98=17/154

Probability of third selection being defective is the sum of all cases,
P(XXD)=P(DDD)+P(DdD)+P(dDD)+P(ddD)
=3/20

5 0

3 years ago

A cube has a volume of 1331 cm3. What is the area of one of its faces.

Vinvika [58]

Area = 726 cm squared

3 0

2 years ago