Write 243 as a power of 3

The mass of earth is 5.9 x 10^24. The mass of Pluto is 13,000,000,000,000,000,000,000 kg. Compared to Pluto, how much greater is

nadya68 [22]

5.9 × 10^24 = 5,900,000,000,000,000,000,000,000 minus
13,000,000,000,000,000,000,000 equals
5,887,000,000,000,000,000,000,000 kg
which is the amount greater that Earth's mass is. you could write this problem as
5.9 × 10^24 - 13 × 10^21 = 5.887 × 10^21

7 0

4 years ago

Pl help it’s for a grade

frosja888 [35]

Answer:

A,d,e not sur tho

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Javier has four cylindrical models. The heights, radii, and diagonals of the vertical cross-sections of the models are shown in

Ronch [10]

The model in which the lateral surface meets the base at right angle is : Model 1.

<h3>What is a lateral surface?</h3>

The lateral surface of an object is all surfaces of that object excluding its base and top.

Analysis:

To know the exact model, we check for the models in which their dimensions form a Pythagorean triplet otherwise a right-angled triangle.

For Pythagorean triplet, the square of the diagonal must be equal to the sum of squares of the other two sides.

Model 1

Diagonal = 50cm, radius = 14cm, lateral height = 48cm

$(50)^{2}$ = $(14)^{2}$ + $(48)^{2}$

2500 = 196 + 2304

2500 = 2500. Forms Pythagorean triplet

Model 2

Diagonal= 37cm, radius = 6cm lateral height = 35cm

$(37)^{2}$ = $(35)^{2}$ + $(6)^{2}$

1369 = 1225 +36

1369 $\neq$ 1261

Model 3

Diagonal = 60cm, radius = 20cm lateral height = 40cm

$(60)^{2}$ = $(20)^{2}$ + $(40)^{2}$

3600 = 400 + 1600

3600 $\neq$ 2000

Model 4

Diagonal = 30cm, radius = 24cm, lateral height = 9cm

$(30)^{2}$ = $(24)^{2}$ + $(9)^{2}$

900 = 576 + 81

900 $\neq$ 657

Therefore the lateral surface model 1 meets the base at right angle

In conclusion, the lateral surface of model 1 meets the base at right angles as the dimensions form a right-angled triangle.

Learn more about Pythagorean triplet: brainly.com/question/20894813

#SPJ1

5 0

2 years ago

Read 2 more answers

Me QR goes through points Q(0, 1) and R(2, 7). Which equation represents line QR?

maks197457 [2]

We write the equation in the form of directional.

y -1 = 6x ⇔ y = 6x + 1

y - 1 = 3x ⇔ y = 3x + 1

y - 7 = 2x - 6 ⇔ y = 2x - 6 + 7

y = 2x + 1

y - 7 = x - 2 ⇔ y = x - 2 + 7

y = x + 5

Equations cleverly arranged .

Point Q = (0,1)

b factor , not only fits the last equation

In the drawing have engraved points Q and R are tangent linear function appropriate to that point . This graphics solution . y = 3x + 1

Answer b

We check choice by the system of equations , where substitute wartoćsi points Q and R to the model equations linear function

The result of equations confirmed our choice Answer b

3 0

2 years ago

When a child is more than two standard deviations underweight for his or her age, the child is suffering from a condition called

SOVA2 [1]

Stunting is the impaired growth and development that children experience from poor nutrition, repeated infection, and inadequate psychosocial stimulation. Children are defined as stunted if their height-for-age is more than two standard deviations below the child growth standard

3 0

3 years ago