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vlabodo [156]
3 years ago
8

Find the value of x in the triangle shown below.

Mathematics
1 answer:
FrozenT [24]3 years ago
5 0
I think it’s 55 lollll
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State the domain of the relation ? ( there is more than one?) select all that apply
Roman55 [17]

Answer:

I think it's {3, 6, 12, 18}

Step-by-step explanation:

Domain: all x-values that are to be used (independent values).

7 0
3 years ago
PLEASE HELP NEED TO KNOW ASAP
ira [324]
6. three kids and four adults
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What is the answer to 9+3/4x=7/8x-10
kolezko [41]
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4 0
3 years ago
SOLVE. integration of (1-v) /(1+v^2)
Nutka1998 [239]
\displaystyle\int\frac{1-v}{1+v^2}\,\mathrm dv=\int\frac{\mathrm dv}{1+v^2}-\int\frac v{1+v^2}\,\mathrm dv

The first integral is already standard and has an antiderivative in terms of \arctan v. For the second integral, take w=1+v^2 so that \dfrac{\mathrm dw}2=v\,\mathrm dv. Then

\displaystyle\int\frac{\mathrm dv}{1+v^2}-\int\frac v{1+v^2}\,\mathrm dv=\arctan v-\frac12\int\frac{\mathrm dw}w
=\arctan v-\dfrac12\ln|w|+C
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4 0
3 years ago
The volume of an object is equal to the ratio of its mass to density, V = StartFraction m Over d EndFraction. The mass of a sphe
Vladimir79 [104]

Answer:

<h2>R=1.0 cm</h2>

Step-by-step explanation:

V=m/d

V=8.4g/(2g/cm³)=4.2cm³

V=4 π R³/3 ;  π≅3.14

R³ =3V/(4 π)=3*4.2cm³/(4*3.14)=12.6cm³/12.56 ≅ 1.0 cm³

=>R=∛(1.0 cm³) =1.0 cm

7 0
3 years ago
Read 2 more answers
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