Answer:
The likelihood that the professor's socks matched his pants on both days is 0.5625
Step-by-step explanation:
Total no. of pair of socks = 24
No. of black pairs = 18
We are given that he selects one pair of socks on Monday and one on Tuesday. Since he has lots of clean socks in the drawer he does not do laundry.
So, It is a case of replacement
He always wears black pants.
We are supposed to find he likelihood that the professor's socks matched his pants on both days i.e. Black socks both days.
So ,Probability of wearing black socks on Monday = 
So ,Probability of wearing black socks on Tuesday =
So,the likelihood that the professor's socks matched his pants on both days = 
Hence the likelihood that the professor's socks matched his pants on both days is 0.5625
Y=.25x+176.10 Y is the monthly cost and B would be the cost of the insurance every month. X is the amount of miles driven since the .25 stays constant but the amount of miles you drive in a month is different every month, Hence, needs to be a variable that can be adjusted,
Answer:
a=1/2
Step-by-step explanation:
3 9/100 would be written as a decimal like this, 3.09. You say three and nine one hundredths. The 9 has to be in the hundredths place, so you put a 0 in front of it. And since the 3 is hole, you put it in front of the decimal point.
I think you would multiply 223 with 15 then divide that number with 792. That’s what I’m guessing