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Zielflug [23.3K]
3 years ago
12

13. Which comparison is correct?

Mathematics
1 answer:
aliya0001 [1]3 years ago
6 0

Answer:

the answer is d

Step-by-step explanation:

I'm smurt

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1) Let f(x)=6x+6/x. Find the open intervals on which f is increasing (decreasing). Then determine the x-coordinates of all relat
brilliants [131]

Answer:

1) increasing on (-∞,-1] ∪ [1,∞), decreasing on [-1,0) ∪ (0,1]

x = -1 is local maximum, x = 1 is local minimum

2) increasing on [1,∞), decreasing on (-∞,0) ∪ (0,1]

x = 1 is absolute minimum

3) increasing on (-∞,0] ∪ [8,∞), decreasing on [0,4) ∪ (4,8]

x = 0 is local maximum, x = 8 is local minimum

4) increasing on [2,∞), decreasing on (-∞,2]

x = 2 is absolute minimum

5) increasing on the interval (0,4/9], decreasing on the interval [4/9,∞)

x = 0 is local minimum, x = 4/9 is absolute maximum

Step-by-step explanation:

To find minima and maxima the of the function, we must take the derivative and equalize it to zero to find the roots.

1) f(x) = 6x + 6/x

f\prime(x) = 6 - 6/x^2 = 0 and x \neq 0

So, the roots are x = -1 and x = 1

The function is increasing on the interval (-∞,-1] ∪ [1,∞)

The function is decreasing on the interval [-1,0) ∪ (0,1]

x = -1 is local maximum, x = 1 is local minimum.

2) f(x)=6-4/x+2/x^2

f\prime(x)=4/x^2-4/x^3=0 and x \neq 0

So the root is x = 1

The function is increasing on the interval [1,∞)

The function is decreasing on the interval (-∞,0) ∪ (0,1]

x = 1 is absolute minimum.

3) f(x) = 8x^2/(x-4)

f\prime(x) = (8x^2-64x)/(x-4)^2=0 and x \neq 4

So the roots are x = 0 and x = 8

The function is increasing on the interval (-∞,0] ∪ [8,∞)

The function is decreasing on the interval [0,4) ∪ (4,8]

x = 0 is local maximum, x = 8 is local minimum.

4) f(x)=6(x-2)^{2/3} +4=0

f\prime(x) = 4/(x-2)^{1/3} has no solution and x = 2 is crtitical point.

The function is increasing on the interval [2,∞)

The function is decreasing on the interval (-∞,2]

x = 2 is absolute minimum.

5) f(x)=8\sqrt x - 6x for x>0

f\prime(x) = (4/\sqrt x)-6 = 0

So the root is x = 4/9

The function is increasing on the interval (0,4/9]

The function is decreasing on the interval [4/9,∞)

x = 0 is local minimum, x = 4/9 is absolute maximum.

5 0
3 years ago
Find the area of this composite figure step by step
xenn [34]

Step-by-step explanation:

areas of the figure = 130.25 ft ².

plz mark my answer as brainlist plzzzz vote me also.

<em>hope </em><em>this</em><em> will</em><em> be</em><em> helpful</em><em> to</em><em> you</em><em> </em><em> </em><em>.</em>

4 0
3 years ago
Read 2 more answers
What is the equation in point slope form of the line that passes through the point
ch4aika [34]

Point-slope form:  y - y₁ = m(x - x₁)

[m is the slope, x₁ and y₁ ---> (x₁, y₁) is the point]

Since you know:

m = 5

(2, 6) = (x₁, y₁)       Substitute/plug in the values into the equation

y - y₁ = m(x - x₁)

y - 6 = 5(x - 2)   The 1st option is your answer

8 0
3 years ago
Please answer this question quickly!
mixer [17]

40 \times 15 = 600 \div 3 = 200m \: and \: the \: formula \: is \: to \: divide \: and \: multipliction
6 0
3 years ago
Find the missing side. Round your answer to the nearest tenths.<br><br> X=
Lapatulllka [165]

Answer:

   16.5 ≈ x

Step-by-step explanation:

We have a right triangle where we know 1 side, 1 angle and we need to find another side. We can use trigonometric functions to find the missing side.

The tangent function definition is

tan α = opposite side/ adjacent side

In our problem

   tan 70° = x/ 6, multiply both sides by 6 to isolate x

6 · tan 70° = x, use the calculator (make sure is set in degrees)

    16.4848 ≈ x , round to the nearest tenths

         16.5 ≈ x


3 0
2 years ago
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