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3 years ago

I really bad at this Yes No

Mathematics

1 answer:

ASHA 777 [7]3 years ago

5 0

Answer:

true yes

Step-by-step explanation:

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(x + 3)^2 = 12 ? need answers ASAP

blsea [12.9K]

Answer:

option c is the correct answer

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3 years ago

What is the value for B, after the equation cap a equals start fraction three over seven end fraction left parenthesis cap b min

r-ruslan [8.4K]

Answer:

$B = \frac{7}{3}A + 25$

Explanation:

The given equation is:

$A = \frac{3}{7} (B-25)$

To get the value of B, we will need to isolate it on one side of the equation

This is done as follows:

$A = \frac{3}{7} (B-25)$

1- Multiply both sides by $\frac{7}{3}$ to get rid of the fraction:

$\frac{7}{3}A = B - 25$

2- Add 25 to both sides of the equation:

$\frac{7}{3} A + 25 = B$

Based on the above:

$B = \frac{7}{3}A + 25$

Hope this helps :)

3 0

3 years ago

Verify sinx/1-cosx + sinx/1+cosx = 2cscx

Andru [333]

$\displaystyle \\ 
 \frac{\sin x}{1-\cos x} + \frac{\sin x}{1+\cos x} = \\ \\ 
 =\frac{\sin x(1+\cos x)}{(1-\cos x)(1+\cos x)} + \frac{\sin x(1-\cos x)}{(1+\cos x)(1-\cos x)} = \\ \\ 
 =\frac{\sin x+\sin x\cos x}{1-\cos^2x} + \frac{\sin x-\sin x\cos x}{1-\cos^2x} = \\ \\ 
 =\frac{\sin x+\sin x\cos x + \sin x-\sin x\cos x}{1-\cos^2x} = \\ \\ 
=\frac{2\sin x }{\sin^2x} = \frac{2 }{\sin x} =2 \times \frac{1 }{\sin x} = 2 \times \csc x = \boxed{2\csc x }$

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3 years ago

Ruben bought 6 books for 21 $.each comic book was the same price

Tomtit [17]

Answer:

$3.50 each book

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Solve for 2cos^2theta + 13costheta = -6. theta is >= 0 and < 360 degrees

LiRa [457]

$\\ 2cos^2 \theta+13cos \theta=-6 \\ 2cos^2 \theta+13cos \theta+6=0 \\ 2cos^2 \theta+12cos \theta+1cos \theta+6=0 \\ 2cos \theta(cos \theta+6)+1(cos \theta+6)=0 \\ (2cos\theta +1)(cos\theta+6)=0 \\$

$cos\theta+6=0 \\ cos\theta=-6 \\ \\ cos(x)=|a| \leq 1 \\ |-6| \geq 1 \\ \\$

$2cos \theta+1=0 \\ 2cos \theta=-1 \\ cos \theta=- \frac{1}{2} \\ \theta= \frac{ 2\pi }{3} +2 \pi k~~~k \in Z \\ \\ 0 \leq \theta \ \textless \ 360^{а} \\ 0 \leq \theta \ \textless \ 2 \pi \\ \theta = \frac{2 \pi }{3} \\ \theta = \frac{2 \pi }{3} , \frac{4 \pi }{3}$

7 0

3 years ago