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iren [92.7K]
3 years ago
7

Does 36 and 21 form a proportion​

Mathematics
1 answer:
Arisa [49]3 years ago
7 0

Answer:

yes

Step-by-step explanation:

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A taco shop is offering a 20% discount on their nacho plate. The original cost of the nacho plate is $15. After applying the dis
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Answer:

3$

Step-by-step explanation:

To find percentage on a discount like this all you have to do is multiply the pre-discount number by your discount percentage.

So all you have to do is:

15 x 0.20

which gives you an answer of 3.

Thus the post-discount amount is $3.

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3 years ago
A box contains 15 nickels and 5 quarters what is the ratio of quarters to nickels
Nastasia [14]
This problem is unsolvable with the answers you gave. The ratio of quarters to nickels would be 5 to 15, or 1 to 3 for fractions.
5 0
3 years ago
In the equation , 2(4x + 3) - 5x = 1, what is the first step that should be taken to solve for x?
Tems11 [23]
Distribute the 2 among the terms inside the parentheses. in other words just multiply the 2 with the numbers inside the parentheses.
5 0
3 years ago
Read 2 more answers
HALLP QUICKKKK
Rina8888 [55]
To solve this we are going to use the formula for speed: S= \frac{d}{t}
where
S is the speed
d is the distance 
t is the time 

Let S_{l} be the speed of the boat in the lake, S_{a} the speed of the boat in the river, t_{l} the time of the boat in the lake, and t_{a} the time of the boat in the river. 

We know for our problem that <span>the current of the river is 2 km/hour, so the speed of the boat in the river will be the speed of the boat in the lake minus 2km/hour:
</span>S_{a}=S_{l}-2
We also know that in the lake the boat<span> sailed for 1 hour longer than it sailed in the river, so:
</span>t_{l}=t_{a}+1
<span>
Now, we can set up our equations.
Speed of the boat traveling in the river:
</span>S_{a}= \frac{6}{t_{a} }
But we know that S_{a}=S_{l}-2, so:
S_{l}-2= \frac{6}{t_{a} } equation (1)

Speed of the boat traveling in the lake:
S_{l}= \frac{15}{t_{l} }
But we know that t_{l}=t_{a}+1, so:
S_{l}= \frac{15}{t_{a}+1} equation (2)

Solving for t_{a} in equation (1):
S_{l}-2= \frac{6}{t_{a} }
t_{a}= \frac{6}{S_{l}-2} equation (3)

Solving for t_{a} in equation (2):
S_{l}= \frac{15}{t_{a}+1}
t_{a}+1= \frac{15}{S_{l}}
t_{a}=\frac{15}{S_{l}}-1
t_{a}= \frac{15-S_{l}}{S_{l}} equation (4)

Replacing equation (4) in equation (3):
t_{a}= \frac{6}{S_{l}-2}
\frac{15-S_{l}}{S_{l}}=\frac{6}{S_{l}-2}

Solving for S_{l}:
\frac{15-S_{l}}{S_{l}}=\frac{6}{S_{l}-2}
(15-S_{l})(S_{l}-2)=6S_{l}
15S_{l}-30-S_{l}^2+2S_{l}=6S_{l}
S_{l}^2-11S_{l}+30=0
(S_{l}-6)(S_{l}-5)=0
S_{l}=6 or S_{l}=5

We can conclude that the speed of the boat traveling in the lake was either 6 km/hour or 5 km/hour.
3 0
4 years ago
The standard height from the floor to the bull's-eye at which a standard dartboard is hung is 5 feet 8 inches. A standard dartbo
pentagon [3]

Answer:

Pls varienton of trigonometric position

Step-by-step explanation:

3 0
2 years ago
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