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Tresset [83]
3 years ago
10

R17 is greater than or equal to 545.7

Mathematics
1 answer:
zhuklara [117]3 years ago
7 0

Answer:

r17 is that a mistake or actually the number?

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100 POINTS FOR THIS!!!
OLga [1]

Answer:

b 56°

a 71°

d 19°

c 127°

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4 0
3 years ago
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Eloise started to solve a radical equation in this way: Square root of negative 2x plus 1 − 3 = x Square root of negative 2x plu
andreyandreev [35.5K]
Here I copy the steps and indicate where the error is.

Square root of negative 2x plus 1 − 3 = x=> <span>this is the starting equation
</span>

√[ - 2x + 1] - 3 = x

Square root of negative 2x plus 1 − 3 + 3 = x + 3 in this step she added 3 to each side, which is fine

<span> Square root of negative 2x plus 1 = x + 3 <span>she made the addtions => fine</span></span>

Square root of negative 2x plus 1 − 1 = x + 3 – 1 due to <span>plus 1 in inside the square root, this step will not help</span>

<span> Square root of negative 2 x = x + 2 <span>wrong! she cannot simplify - 1 that is out of the square root with +1 that is inside the square root
</span></span>


<span>Then, from here on all is wrong, but she made other additional mistakes.</span>

(Square root of negative 2 x)2 = (x − 4)2 −2x <span> the right side should be (x+2)^2 which is x^2 + 4x +4 not (x-4)^2 - 2x</span>

Later she made a mistake changing the sign of -8x to +8x


Those are the mistakes. Finally, the global error is that she should verify whether the found values satisfied the original equation.

3 0
3 years ago
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Triangle ABC has vertices at A(−1 , 2), B(4, 2), and C(3, −1). Classify the triangle according to the side lengths.
Orlov [11]

Answer:

B) Isosceles

Step-by-step explanation:

The given triangle has vertices at A(-1,2), B(4,2) and C(3,-1).

We must first determine the length of the sides of the triangle, before we can classify it.

We apply the distance formula to find length of the sides.

|AB|=\sqrt{(4--1)^2+(2-2)^2}

\Rightarrow |AB|=\sqrt{(4+1)^2+(2-2)^2}

\Rightarrow |AB|=\sqrt{5^2+(0)^2}

\Rightarrow |AB|=\sqrt{25}

\Rightarrow |AB|=5 units.

The length of side BC

|BC|=\sqrt{(3-4)^2+(-1-2)^2}

\Rightarrow |BC|=\sqrt{(-1)^2+(-3)^2}

\Rightarrow |BC|=\sqrt{1+9}

\Rightarrow |BC|=\sqrt{10}

The length of side AC

|AC|=\sqrt{(3--1)^2+(-1-2)^2}

We simplify to obtain;

|AC|=\sqrt{(3+1)^2+(-3)^2}

\Rightarrow |AC|=\sqrt{(4)^2+(-3)^2}

|AC|=\sqrt{16+9}

|AC|=\sqrt{25}

|AC|=5\:units

Since |AC|=5\:units=|AB|, the given triangle is an isosceles triangle.

The correct answer is

6 0
3 years ago
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Find the circumference of a circle with radius, r = 16.5m.<br> Give your answer in terms of pi.
Ksenya-84 [330]

Answer:

103.714 approximately 104

Step-by-step explanation:

2^r

2 × 22/7 ×16.5

7 0
3 years ago
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What is the quotient?
Zigmanuir [339]

Answer:

B. Negative two-fifths (-2/5)

Step-by-step explanation:

1. Change the second number into a fraction if it isn't already.

2. Find the reciprocal of the divisor, or second fraction.

3. Multiply the numerators together.

4. Multiply the denominators together.

5. Simplify the answer if possible.

6. Determine if the answer is positive or negative using the sign rules.

Show your work:

-4/5 divided by 2/1

-4/5 divided 1/2

-4 * 1 = -4

5 *  2 = 10

Simplify:

-4/10 = -2/5

8 0
3 years ago
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