Answer:
quantity a is halfed
Corrected question;
A quantity a varies inversely as a quantity b, if, when b changes a changes in the inverse ratio. What happens to the quantity a if the quantity b doubles?
Step-by-step explanation:
Analysing the question;
A quantity a varies inversely as a quantity b,
a ∝ 1/b
a = k/b ......1
when b changes a changes in the inverse ratio;
Since the change at the same ratio but inversely, k = 1
So, equation 1 becomes;
a = 1/b
If the quantity b doubles,
ab = 1
a1b1 = a2b2
When b doubles, b2 = 2b1
a1b1 = a2(2b1)
Making a2 the subject of formula;
a2 = a1b1/(2b1)
a2 = a1/2
Therefore, when b doubles, a will be divided by 2, that means a is halfed.
(6 + 3) + 21 = 6 + (3 + 21)
It's an ASSOCIATIVE PROPERTY
(a + b) + c = a + (b + c)
767 rounded to the nearest ten is 770
Answer:
Step-by-step explanation:
Your friend has a head start of (2 h)×(8 mi/h) = 16 mi.
When you leave, you gain on your friend at the rate of 40 mph - 8 mph = 32 mph. So, it will take ...
(16 mi)/(32 mi/h) = 1/2 h
for you to reduce the distance between you to zero.
In that 1/2 hour, you have traveled ...
(1/2 h)×(40 mi/h) = 20 mi
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This is the same distance your friend has traveled in 2.5 hours at 8 mi/h.
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