$\dfrac{5}{7}\ of\ 100:\\\\\dfrac{5}{7}\cdot100=\dfrac{5\cdot100}{7}=\dfrac{500}{7}=\dfrac{70+28+2}{7}=\dfrac{70}{7}+\dfrac{28}{7}+\dfrac{2}{7}\\\\=10+4+\dfrac{2}{7}=14\dfrac{2}{7}\\\\\dfrac{2}{7}\ \text{is smaller than}\ \dfrac{1}{2}.\ \text{Therefore}\ 14\dfrac{2}{7}\approx14\\\\Answer:\ \boxed{14}$

7 0

3 years ago

A conical vessels with base radius 5 cm and height 24cm is full of water this water is emptied into a cylindrical vessel of base

Aliun [14]

Answer:

$2\ cm$

Step-by-step explanation:

$We\ are\ given\ that,\\Radius\ of\ the\ conical\ vessel=5\ cm\\Height\ of\ the\ conical\ vessel=24\ cm\\Hence,\\As\ we\ know\ that,\\Volume\ of\ a\ cone=\frac{1}{3}\pi r^2h\\Hence,\\The\ volume\ of\ the\ conical\ vessel=\frac{1}{3}\pi (5)^224= \frac{1}{3}\pi 25*24=200\pi \\Hence,\\The\ volume\ of\ the\ conical\ vessel=The\ amount\ of\ water\ filled\ in\ it\\Hence,\\The\ amount\ of\ water\ filled\ in\ the\ conical\ vessel=200\pi\\Lets\ consider\ the\ cylindrical\ vessel:\\Volume\ of\ a\ cylinder=\pi r^2h$

$As\ we\ are\ not\ said\ that\ the\ cylindrical\ vessel\ was\ empty,\ let\ its\ initial\\ height\ be\ h_1\\Radius\ of\ the\ Cylindrical\ vessel=10\ cm\\Initial\ height\ of\ the\ cylindrical\ vessel=h_1\\Initial\ volume\ of\ the\ cylindrical\ vessel=\pi *10^2*h_1=100h_1\pi \\Initial\ amount\ of\ water\ in\ the\ cylindrical\ vessel=100h_1\pi \\Hence,\\Final\ amount\ of\ water\ in\ the\ cylindrical\ vessel=Final\ amount\ of\ water\\ in\ the\ cylindrical\ vessel +Amount\ of\ water\ in\ conical\ vessel$

$Hence,\\Final\ amount\ of\ water\ in\ the\ cylindrical\ vessel=100h_1\pi +200\pi \\Now,\\Let\ the\ final\ height\ be\ h_2\\Hence,\\Final\ amount\ of\ water\ in\ the\ cylindrical\ vessel=\pi *10^2*h_2=100h_2\pi \\Hence,\\100h_2\pi =100h_1\pi +200\pi \\Hence,\\100h_2=100h_1+200\\100h_2-100h_1=200\\100(h_2-h_1)=200\\h_2-h_1=2\\Hence,\\As\ the\ rise\ in\ level\ is\ the\ difference\ between\ the\ initial\ and\ final\\ heights:\\The\ rise\ in\ level\ of\ water=2\ cm$

8 0

3 years ago

Jonathan sold five times as many computers as Joe sold last year. In total,

Rom4ik [11]

Answer:

Step-by-step explanation:

Let the number of computers sold by Joe be represented by variable X

If Jonathan sold 5 times as many computers , it means he sold 5 times X= 5X

Total number of computers sold by both Jonathan and Joe = 78

Hence, X+5X =78

= 6X = 78

Divide both sides by 6 to solve for X;

X = 78/6

X = 13

And 5X = (5* 13) = 65

Therefore, Jonathan sold 65 computers while Joe sold 13

3 0

3 years ago

If there's a how and a guy picks her up who's getting abused​

If there's a how and a guy picks her up who's getting abused