Let the amount deposited (principal) be x, then the amount after the required time = 2x.
A = P(1 + r/n)^nt: where A is the future value = 2x, P is the principal = x, r is the rate = 0.75%, n is the number of accumulation in a year = 12, t is the number of years.
2x = x(1 + 0.0075/12)^12t
2 = (1 + 0.000625)^12t
log 2 = 12t log (1.000625)
log 2 / log (1.000625) = 12t
1109.38 = 12t
t = 92 years
Answer:
(Explanation)
Step-by-step explanation:
Part A:
The graph of y =
+ 2 will be translated 2 units up from the graph of y =
.
If you plug in 0 for x, you get a y-value of 2. The 2 is also not included with the
, which is why it doesn't translate left.
This is what graph A should look like:
[Attached File]
Part B:
The graph of y =
- 2 will be translated 2 units down from the graph of y =
.
If you plug in 0 for x, you get a y-value of -2. The 2 is also not included with the
, which is why it doesn't translate right.
This is what graph B should look like:
[Attached File]
Part C:
The graph of y = 2
is a stretched version of the graph y =
. Numbers that are greater than 1 stretch and open up and numbers less than -1 stretch and open down.
This is what graph C should look like:
[Attached File]
Part D:
The graph of y =
is a compressed version of the graph y =
. Numbers that are in-between 0 and 1, and -1 and 0 are compressed.
This is what graph D should look like:
[Attached File]
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Answer:
48
Step-by-step explanation:
6x4x2