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olya-2409 [2.1K]
3 years ago
11

Please help me if you can. Please also write how you got the answer thank you.

Mathematics
1 answer:
Llana [10]3 years ago
7 0
Let Taylor's earnings be t, Andile's earnings be a and that of Favour be f.
Given that t+a+f=380. Also given that Taylor earned 40 less than Andile. That translates to t=a-40. Favour earned twice as much as Taylor.
That is, f=2t. Substitute t=a-40 into f=2t to get f=2(a-40)=2a-80.

Substitute t=a-40 and c=2a-80 into t+a+f=380 to get
a-40+a+2a-80=380.
Combining like terms, we get 4a-120=380. Adding 120 to both sides of the equation, we get, 4a=500 and dividing by 4 on both sides, we get a=125.

Since we want to know what Taylor earned, substitute a=125 back into t=a-40=125-40=85

Therefore, Taylor earned $85!
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\begin{array}{rcl}\frac{1}{4}x^{2} & = & (x - 3)^{2}\\x^{2} & = & 4(x - 3)^{2}\\& = & 4(x^{2} - 6x + 9)\\x^{2}& = & 4x^{2} - 24x + 36\\3x^{2} - 24x + 36 & = & 0\\x^{2} - 8x + 12 & = & 0\\(x - 2)(x - 6) & = & 0\\x - 2 = 0& \qquad &x - 6 = 0\\x = 2& \qquad &x = 6\\\end{array}

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Check:

\begin{array}{rcl}\frac{1}{4}(6)^{2} & = & (6 - 3)^{2}\\\frac{1}{4}\times 36 & = & 3^{2}\\9 & = & 9\\\end{array}

OK.

3 0
3 years ago
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