Please Help!!!!!! So i know how to reflect over line y=-x but how would i do it over line y=-x+6. An example would be helpful an
1 answer:
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Answer:
8 +
Step-by-step explanation:
From the phrase, the <em>answer</em> is smaller(less) by 8 when compared(equal (=)) to quotient of 5 and w ...
So:
Answer - 8 = quotient of 5 and w
Here, quotient is the whole number from a <em>division</em>. The division here is
Therefore,
Answer - 8 =
Answer = 8 +
Hence the phrase into algebraic expression is 8 +
Answer:
(1) The slope of the line segment AB is 1.
(2) The length of the line segment AB is 10
(3) The coordinates of the midpoint of AB is (5, 7)
(4) The slope of a line perpendicular to the line AB is-0.75
Step-by-step explanation:
The coordinates of the line segment AB are;
A(2, 3) and B(8, 11)
(1) The slope of a line segment is given by the following equation;
Where;
(x₁, y₁) and (x₂, y₂) are two points on the line segment
Therefore;
The slope, m, of the line segment AB is given as follows;
A(2, 3) = (x₁, y₁) and B(8, 11) = (x₂, y₂)
The slope of the line segment AB = 1.
(2) The length, l, of the line segment AB is given by the following equation;
Therefore, we have;
The length of the line segment AB is 10
(3) The coordinates of the midpoint of AB is given as follows;
Therefore;
The coordinates of the midpoint of AB is (5, 7)
(4) The relationship between the slope, m₁, of a line AB perpendicular to another line DE with slope m₂, is given as follows;
Therefore, the slope, m₁, of the line perpendicular to the line AB, that has a slope m₂ = 4/3 = 1. is given as follows;
The slope, m₁, of the line perpendicular to the line AB is m₁ = -0.75.