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Lemur [1.5K]
3 years ago
7

Ava makes bead necklaces. She has a total of 6048 beads. Each necklace has 24 beads. Her friend maria says that the greatest num

ber of necklace she can make with the beads is 162. Marias. Work is shown here
Mathematics
1 answer:
Rama09 [41]3 years ago
8 0

The question is incomplete:

Ava makes bead necklaces. She has a total of 6048 beads. Each necklace has 24 beads. Her friend maria says that the greatest number of necklace she can make with the beads is 162. Marias. Work is shown here. Explain why Maria is incorrect and how she can find the correct answer.

Answer:

Maria is incorrect because when you divide the number of beads by the beads in each necklace, you find that she can make 252 necklaces.

Step-by-step explanation:

You can find the number of necklaces Avan can make by dividing the number of beads she has by the amount in each necklace:

6048/24=252

According to this, you can say that Maria is incorrect because when you divide the number of beads by the beads in each necklace, you find that she can make 252 necklaces.

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3 years ago
Francis is at the state fair. A fair concession stand is selling funnel cakes for $3.50 and deep-fried Oreos for $2.00. Write an
VladimirAG [237]

The equation that models the number of funnel cakes and Oreos he can buy is 3.50x + 2.0y = 42

Data given;

  • Cost of cakes = $3.50
  • Cost of Oreos = $2.00
  • The total amount spent = $42.00
<h3>What is the Equation</h3>

To solve this problem, we just need to write out an equation to show how he can spend $42.00 in the fair on Oreos and Cakes.

Let x represent the cakes

Let y represent the Oreos

The equation is thus;

3.50x + 2.0y = 42.00

The equation that shows the number of Cakes and Oreos can by is

3.50x + 2.0y = 42

Learn more about equation here;

brainly.com/question/13729904

3 0
2 years ago
Solve the following differential equations or initial value problems. In part (a), leave your answer in implicit form. For parts
shepuryov [24]

Answer:

(a) (y^5)/5 + y^4 = (t^3)/3 + 7t + C

(b) y = arctan(t(lnt - 1) + C)

(c) y = -1/ln|0.09(t + 1)²/t|

Step-by-step explanation:

(a) dy/dt = (t^2 + 7)/(y^4 - 4y^3)

Separate the variables

(y^4 - 4y^3)dy = (t^2 + 7)dt

Integrate both sides

(y^5)/5 + y^4 = (t^3)/3 + 7t + C

(b) dy/dt = (cos²y)lnt

Separate the variables

dy/cos²y = lnt dt

Integrate both sides

tany = t(lnt - 1) + C

y = arctan(t(lnt - 1) + C)

(c) (t² + t) dy/dt + y² = ty², y(1) = -1

(t² + t) dy/dt = ty² - y²

(t² + t) dy/dt = y²(t - 1)

(t² + t)/(t - 1)dy/dt = y²

Separating the variables

(t - 1)dt/(t² + t) = dy/y²

tdt/(t² + t) - dt/(t² + t) = dy/y²

dt/(t + 1) - dt/(t(t + 1)) = dy/y²

dt/(t + 1) - dt/t + dt/(t + 1) = dy/y²

Integrate both sides

ln(t + 1) - lnt + ln(t + 1) + lnC = -1/y

2ln(t + 1) - lnt + lnC = -1/y

ln|C(t + 1)²/t| = -1/y

y = -1/ln|C(t + 1)²/t|

Apply y(1) = -1

-1 = ln|C(1 + 1)²/1|

-1 = ln(4C)

4C = e^(-1)

C = (1/4)e^(-1) ≈ 0.09

y = -1/ln|0.09(t + 1)²/t|

8 0
3 years ago
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