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Andrej [43]
3 years ago
13

Find the value of the tangent for

Mathematics
1 answer:
Fynjy0 [20]3 years ago
3 0

Answer:

choice A

Step-by-step explanation:

Sin A=12/40

sin A=.3

angle A=17.4576 degrees

Tan 17.4576=0.3145

Tan A=0.3145

Choice a, 3x(sr root of 91)/91=0.3145

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Which of the following illustrates the truth value of the given statements? 5 is less than 7 or 7 is less than 12.
mylen [45]
The answer is A because it has or in the sentence
8 0
3 years ago
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How does metric conversion work
kotegsom [21]
You can convert between the various different sizes by merely moving the decimal point the correct number of places. The basic metric units are meters (for length), grams (for mass or weight), and liters (for volume).
6 0
3 years ago
Anyone help me. ....​
weeeeeb [17]

Answer:

see explanation

Step-by-step explanation:

Using the rules of exponents

All the exponents inside the parenthesis are multiplied by the exponent outside the parenthesis.

Then

\frac{m^{-7}n^{14}  }{m^{-25}n^{40}  } ÷ \frac{m^{-21}n^{42}  }{m^{-25}n^{40}  }

[ Using the rule \frac{a^{m} }{a^{n} } = a^{(m-n)} ]

= m^{(-7-14)} n^{(14-(-28)} ÷ m^{(-15-10)} n^{(25-(-15)}

= m^{-21} n^{14+28} ÷ m^{-25} n^{25+15}

= \frac{m^{-21}n^{42}  }{m^{-25}n^{40}  }

= m^{(-21-(-25))} n^{(42-40)}

= m^{(-21+25)} n²

= m^{4} n² = m^{x} n^{y} , so x = 4 and y = 2

Then

m^{x-2y} = m^{4-2(2)} = m^{4-4} = m^{0} = 1 ← as required

6 0
3 years ago
An environmentalist wants to find out the fraction of oil tankers that have spills each month. Suppose a sample of 836 tankers i
Alexxandr [17]

Answer:

<em>The 99% confidence interval for the population proportion of oil tankers that have spills each month.</em>

<em>(0.6489 , 0.7311)</em>

Step-by-step explanation:

<u><em>Step(i)</em></u>:-

Given sample size 'n' = 836

Suppose a sample of 836 tankers is drawn. Of these ships, 577 did not have spills.

sample proportion

                    p^{-}  = \frac{x}{n} = \frac{577}{836} = 0.690

<em>The 99% confidence interval for the population proportion is determined by</em>

<em></em>(p^{-} - Z_{0.01} \sqrt{\frac{p(1-p)}{n} } , p^{-} + Z_{0.01} \sqrt{\frac{p(1-p)}{n} })<em></em>

<u><em>Step(ii)</em></u><em>:-</em>

<em>The Z- value = 2.576</em>

<em></em>(0.690 - 2.576 \sqrt{\frac{0.690(1-0.690)}{836} } , 0.690 + 2.576 \sqrt{\frac{0.690(1-0.690)}{836} })<em></em>

<em>On calculation , we get</em>

<em>(0.690 -  0.0411 , 0.690 + 0.0411)</em>

<em>(0.6489 , 0.7311)</em>

<u><em>Final answer</em></u><em>:-</em>

<em>The 99% confidence interval for the population proportion of oil tankers that have spills each month.</em>

<em>(0.6489 , 0.7311)</em>

<em></em>

<em></em>

8 0
4 years ago
Can an expert help me with this
Vinvika [58]

Yes im a teacher from csn a math teacher


4 0
3 years ago
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