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Anuta_ua [19.1K]
3 years ago
15

Survey: On free time 90 students like watching TV, 20 like watching TV but not reading, 80 like reading, 40 do not like watching

TV. Question: Percent of total student like both watching televisan and reading
Mathematics
1 answer:
Dvinal [7]3 years ago
5 0

Answer:

 50 %

Step-by-step explanation:

From the diagram attached,

Percentage of total students that like watching television = [(WnR)/μ]×100......... Equation 1

The number of students that like watching television and reading (WnR) = 70

The total number of students (μ) = 40+20+70+10

The total number of students (μ) = 140

Substitute these values into equation 1

Percentage of total students that like watching television = (70/140)×100

Percentage of total students that like watching television = 1/2(100)

Percentage of total students that like watching television = 50 %

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AlexFokin [52]

Answer:

AE = 60 units

Step-by-step explanation:

GE is one third the length of AE so...

GE = 1/3(AE)

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7 0
3 years ago
A box contain 12 balls in which 4 are white 3 are blue and 5 are red.3 balls are drawn at random from the box.find the chance th
Anastasy [175]

Answer:

3/11

Step-by-step explanation:

From the above question, we have the following information

Total number of balls = 12

Number of white balls = 4

Number of blue balls = 3

Number of red balls = 5

We solve this question using combination formula

C(n, r) = nCr = n!/r!(n - r)!

We are told that 3 balls are drawn out at random.

The chance/probability of drawing out 3 balls = 12C3 = 12!/3! × (12 - 3)! = 12!/3! × 9!

= 12 × 11 × 10 × 9 × 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1/(3 × 2 × 1) × (9 × 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1)

= 220 ways

The chance of selecting 3 balls at random = 220

To find the chance that all the three balls are selected,

= [Chance of selecting (white ball) × Chance of selecting(blue ball) × Chance of selecting(red balls)]/ The chance/probability of drawing out 3 balls

Chance of selecting (white ball)= 4C1

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Hence,

= [4C1 × 3C1 × 5C1]/ 220

= 60/220

= 6/22

= 3/11

The chance that all three are selected is = 3/11

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Answer:

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