Answer:
136° that's 90 plus 46.........
Answer:
D
Step-by-step explanation:
check each child answer and multiply by 4.50
check each adult answer and multiply by 6.00
add both answers up
and see which one it is
its not A, B, or C
Answer:
94
Step-by-step explanation:
Gary=47 ounce
friend =47 ounce
47 ounce +47 ounce =94 ounce
Answer:
197,8879 N.
Step-by-step explanation:
The magnitude of the horizontal force exerted on the statue can be calculated using trigonometric functions.
The question given says that Nancy is pushing the statue with a force of 120 N at a 60° angle to the horizontal and Harry is pulling the statue with a force of 180 N at a 40° angle with the horizontal.
With that information can be calculated the horizontal force exerted on the statue by Nancy, the horizontal force exerted on the statue by Harry and, adding that results, the total horizontal magnitude can be calculated.
The cosine function can be used to calculate the horizontal component of the forces exerted by Nancy and Harry, to determine the horizontal component of the force exerted on the statue.
F= (120 N cos 60°) + (180 N x cos 40°)
F= 197,8879 N
Answer:
11 units
Step-by-step explanation:
<em>hey there,</em>
<em />
< A square has 4 sides that are all always equal to each other. The perimeter is all the sides summed up together. That means (for example), if one side of the square is 2 cm, then we know that the perimeter is 8 cm, because 2 + 2 + 2 + 2 = 8 (or 2×4=8).
Here we are given that one side is equal to "x-5". Pretend that is a number and solve as I did just right above:
(x-5)×4 = 4x -20
Now we know that the perimeter is (4x-20) units (when you don't know what the units are then just put "units").
We also know that the perimeter can be a number which is 24. That means these two values are equal to each other.
4x-20 = 24
Now solve! Bring x to one side, and all the numbers to the other side.
4x = 44
x = 11
We now know that the value of one side of the square (x) is equal to 11 units. >
<u>Hope this helped! Feel free to ask anything else.</u>