PLEASE HELP ME!!!! I WILL MARK!!!
1 answer:
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Answer:
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Step-by-step explanation:
The fastest way to do this is to convert both equations into slope-intercept form and graph it to find the solution point. If you wanted to do this algebraically, you might want to start out by getting rid of the fractions and using either substitution or elimination to find x and y.
Answer:
12. 1 second, 35 ft; 2 seconds, 32 ft
13. (t, y) = (1.4 seconds, 37.6 feet)
14. 37.6 ft; the vertex is the highest point
Step-by-step explanation:
12. You have properly answered question 12.
After 1 second, the height is 35 feet; after 2 seconds, it is 32 feet.
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13. My method of choice is to plot the graph on a graphing calculator and let it show me the coordinates of the vertex when I highlight that point. (See attached.) The vertex is ...
(t, y) = (1.4, 37.6)
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14. The graph is a graph of height when the object is launched with a vertical velocity of 45 ft/s. So, the maximum of the graph will correspond to the maximum height of the object. The vertex is that maximum point, and its y-coordinate is that maximum height.
The maximum height is 37.6 feet.
Answer:
x ≈ 11.1
Step-by-step explanation:
Using the cosine ratio in the right triangle.
cos42° = =
( multiply both sides by 15 )
15 × cos42° = x, then
x ≈ 11.1 ( to the nearest tenth )