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Trava [24]
3 years ago
13

-5/6+?=a negative number PLS HELP

Mathematics
2 answers:
Aleks04 [339]3 years ago
7 0

Answer:

Any number less than 5/6 would work

Examples: 2/3, 1/2, 0, -1, -4, -100

jasenka [17]3 years ago
5 0

Answer:

no its not a negative number

Step-by-step explanation:a negative number is less than zero

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What is the value of x? How do you set up to solve?
nlexa [21]

Answer:

3x-22=80+x

3x-x=80+22

2x=102

x=51

Step-by-step explanation:

the exterior angle is (3x-22) and then is equal to sum of 80 and x

and then we get 51

6 0
2 years ago
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What is the constant of posprtainality in the equation y=0.41
KATRIN_1 [288]

Answer:

The constant of proportionality in the equation y=0.41 is 0.41

Step-by-step explanation:

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3 years ago
Factor using the identity: a3 + b3 = (a + b)(a2 – ab + b2) 8z3 + 27
vivado [14]

Answer:  this is our required factor i.e.

8z^3+27=(2z+3)(4z^2-6z+9)

Explanation:

Since we have given that

8z^3+27

As we know the identity , which says that

a^3+b^3=(a+b)(a^2-ab+b^2)

So, we can use this here ,

8z^3+27=(2z)^3+3^3\\\\=(2z+3)((2z)^2-2z\times 3+3^2)\\\\=(2z+3)(4z^2-6z+9)

Hence this is our required factor i.e.

8z^3+27=(2z+3)(4z^2-6z+9)


7 0
3 years ago
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What percent is 50% of 50% of x
kiruha [24]

Answer:

um the best i can say is 25% if thats the only info you give

Step-by-step explanation:

6 0
3 years ago
A B R and P are four points on a circle with centre 0. A O R and C are four points on a different circle. The two circles inters
Slav-nsk [51]

Answer:

x° = ∠OBR = ∠ABC (base angles of a cyclic isosceles trapezoid)

Step-by-step explanation:

APRB form a cyclic trapezoid

∠APO  = x° (Base angle of an isosceles triangle)

∠OPR  = ∠ORP (Base angle of an isosceles triangle)

∠ORB = ∠OBR (Base angle of an isosceles triangle)

∠APO + ∠OPR + ∠OBR = 180° (Sum of opposite angles in a cyclic quadrilateral)

Similarly;

∠ORB + ∠ORP + x°  = 180°

Since ∠APO = x° ∠ORB = ∠OBR and ∠OPR  = ∠ORP we put

We also have;

∠OPR = ∠AOP = ∠BOR (Alternate interior angles of parallel lines)

Hence 2·x° + ∠AOP = 180° (Sum of angles in a triangle) = 2·∠OBR + ∠BOR

Therefore, 2·x° = 2·∠OBR, x° = ∠OBR = ∠ABC.

6 0
3 years ago
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