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2 years ago

Is this correct?? if not pls tell me the correct answer

Mathematics

2 answers:

slamgirl [31]2 years ago

8 0

Answer:

no, but it is A.

kkurt [141]2 years ago

5 0

A is the correct answer

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Let S be the solid beneath z = 12xy^2 and above z = 0, over the rectangle [0, 1] × [0, 1]. Find the value of m > 1 so that th

jonny [76]

Answer:

The answer is $\sqrt{\frac{6}{5}}$

Step-by-step explanation:

To calculate the volumen of the solid we solve the next double integral:

$\int\limits^1_0\int\limits^1_0 {12xy^{2} } \, dxdy$

Solving:

$\int\limits^1_0 {12x} \, dx \int\limits^1_0 {y^{2} } \, dy$

$[6x^{2} ]{{1} \atop {0}} \right. * [\frac{y^{3}}{3}]{{1} \atop {0}} \right.$

Replacing the limits:

$6*\frac{1}{3} =2$

The plane y=mx divides this volume in two equal parts. So volume of one part is 1.

Since m > 1, hence mx ≤ y ≤ 1, 0 ≤ x ≤ $\frac{1}{m}$

Solving the double integral with these new limits we have:

$\int\limits^\frac{1}{m} _0\int\limits^{1}_{mx} {12xy^{2} } \, dxdy$

This part is a little bit tricky so let's solve the integral first for dy:

$\int\limits^\frac{1}{m}_0 [{12x \frac{y^{3}}{3}}]{{1} \atop {mx}} \right.\, dx =\int\limits^\frac{1}{m}_0 [{4x y^{3 }]{{1} \atop {mx}} \right.\, dx$

Replacing the limits:

$\int\limits^\frac{1}{m}_0 {4x(1-(mx)^{3} )\, dx =\int\limits^\frac{1}{m}_0 {4x-4x(m^{3} x^{3} )\, dx =\int\limits^\frac{1}{m}_0 ({4x-4m^{3} x^{4}) \, dx$

Solving now for dx:

$[{\frac{4x^{2}}{2} -\frac{4m^{3} x^{5}}{5} ]{{\frac{1}{m} } \atop {0}} \right. = [{2x^{2} -\frac{4m^{3} x^{5}}{5} ]{{\frac{1}{m} } \atop {0}} \right.$

Replacing the limits:

$\frac{2}{m^{2} }-\frac{4m^{3}\frac{1}{m^{5}}}{5} =\frac{2}{m^{2} }-\frac{4\frac{1}{m^{2}}}{5} \\ \frac{2}{m^{2} }-\frac{4}{5m^{2} }=\frac{10m^{2}-4m^{2} }{5m^{4}} \\ \frac{6m^{2} }{5m^{4}} =\frac{6}{5m^{2}}$

As I mentioned before, this volume is equal to 1, hence:

$\frac{6}{5m^{2}}=1\\m^{2} =\frac{6}{5} \\m=\sqrt{\frac{6}{5} }$

3 0

3 years ago

Describe how to write 3x+2y=12 in function notation. Assume that y represents the dependant variable.

kotegsom [21]

Im not so sure but, 3x2=6; 2x3=6; 6+6=12

5 0

3 years ago

Which costs more per notebook, a 4-pack of notebooks for $3.98 or a 5-pack of notebooks for $4.99? Explain

avanturin [10]

Answer:

5 pack notebook

Step-by-step explanation:

5 pack notebook costs more because the 4 pack notebook costs 4 dollars w/ 2 cents off, and 5 pack notebook costs 5 dollars and with 1 cent of, so if ir increase by 1 dollar, than probably the 5 pack costs more. It is not about how many, but how much dollars are for per/ notebook.

7 0

3 years ago

What is the answer!???

mr Goodwill [35]

I believe A is the answer!

3 0

3 years ago

What is 3a+2c=26 solve for a and c

blondinia [14]

Simplifying

3a + 2b + c = 26

Solving

3a + 2b + c = 26

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-2b' to each side of the equation.

3a + 2b + -2b + c = 26 + -2b

Combine like terms: 2b + -2b = 0

3a + 0 + c = 26 + -2b

3a + c = 26 + -2b

Add '-1c' to each side of the equation.

3a + c + -1c = 26 + -2b + -1c

Combine like terms: c + -1c = 0

3a + 0 = 26 + -2b + -1c

3a = 26 + -2b + -1c

Divide each side by '3'.

a = 8.666666667 + -0.6666666667b + -0.3333333333c

Simplifying

a = 8.666666667 + -0.6666666667b + -0.3333333333c

3 0

3 years ago

Read 2 more answers