Answer:
Power is measured at three different levels pertinent to flapping flight. The first level is metabolic power input (P met) to the muscles, directly of interest to a flying, foraging bird, and generally a realm of study for respiratory, thermal and chemical physiologists.P met is the rate the bird expends chemical energy to supply the flight muscles, and it may be measured using double-labeled
Answer:
50%
Explanation:
Both parent's genotype is Bb because they are hairless and alive.
If it has a homozygous dominant genotype (BB), the dog will die in utero.
If it has a heterozygous genotype (Bb), the dog will be hairless but won't die.
If it has a homozygous dominant genotype (bb), the dog will have hair.
The ratio of BB:Bb:bb is 1:2:1 meaning that there is a 50% probability of having a live hairless puppy.
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Answer:
3 and 4 are both Aa
8 and 9 cannot be h0m0zygous.
Explanation:
Individual 3 and 4 are non-shaded, which means they are either AA or Aa.
They have three children, 9, 10, and 11. 9 and 11 are also non-shaded, meaning they are either AA or Aa.
However, 10 is shaded, which means he is aa.
For 10 to be aa, he must have gotten one a allele from each parent. Therefore, 3 and 4 must both be heterozygous Aa.
8 and 9 are both non-shaded, which means they are either AA or Aa.
They have three children, 13 is non-shaded, so either AA or Aa.
12 and 14 are both shaded, which means they are both aa. They much each have inherited an a allele from each parent.
This means it is impossible for individuals 8 and 9 to be h0m0zygous.
